eval giving the wrong mathematical answer

I'm trying to write a script that I will use for Newton Rhapson approximation. I am testing as I go and I noticed that the eval command is returning the incorrect mathematical answer. I am testing it with x=2 with func=((2*x)*(log(x)))-1
Here is the code:
syms x;
func=input('Enter your function in terms of x: ');
f=@(x)(func);
z=diff(f(x));
f1=@(x)(z);
x0=input('Enter your initial value of x: ');
x=x0
s=char(f1);
y=subs(f1)
eval(y)
Upon entering x=2 and func=((2*x)*(log(x)))-1
The code redturns:
x =
2
y =
2*log(2) + 2
ans =
3.3863
The answer to 2*log(2)+2 should be 2.602
What am I doing wrong?

Respuestas (1)

Roger Stafford
Roger Stafford el 22 de Feb. de 2015

1 voto

In matlab the 'log' function is considered to be the natural logarithm with base e, not 10. Therefore 3.3863 is the correct answer, not 2.602 .

1 comentario

John D'Errico
John D'Errico el 22 de Feb. de 2015
Editada: John D'Errico el 22 de Feb. de 2015
And of course, if you really wanted a log to the base 10, use log10.
2*log10(2)+2
ans =
2.6021
Computers are so silly. They do what you tell them to do, instead of what you want them to do.

Iniciar sesión para comentar.

Categorías

Más información sobre Interpolation en Centro de ayuda y File Exchange.

Preguntada:

el 22 de Feb. de 2015

Editada:

el 22 de Feb. de 2015

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by