Join two table variables into one. == does not works of table type
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Hello everybody,
I have two table variables, and would like to join them.
After comparing 1st column to 7th column of df3 and df4 variables,
if the row from 1st to 7th column is exactly same, then I hope to add the test2 column of df4
into dfcombine variable.
Please give me some helps.... == does not works of table type.
load input03.mat
dfcombine = df3;
for i=1:height(df3)
ind = find(df3(i,1:7)==df4(:,1:7));
dfcombine(i,9) = df4(ind,8);
end
I hope to make the dfcombine variable as below picture.

Respuesta aceptada
Más respuestas (2)
Walter Roberson
el 22 de Sept. de 2022
0 votos
You are doing () indexing on a table. The result would be a table row. You compare that to something else that is probably a table. But two tables can only compare if the variable names are the same... which we do not know to be true.
1 comentario
Smithy
el 22 de Sept. de 2022
HYEONSEOK SEOK
el 22 de Sept. de 2022
0 votos
For comparing something with logical, table need to change to array
see as below:
clear all ; close all; clc;
load("input03.mat")
for i = 1:height(df3)
for j = 1:7
for k = 1:height(df4)
if sum(j == [5,6])
checker(k,j)=sum((df3{i,j}==df4{k,j}),1);
else
checker(k,j)=sum(strcmp(df3{i,j},df4{k,j}),1);
end
end
end
if sum(sum(checker,2) > 5) % if no nan value - change to 6
test2(i,1) = df4((sum(checker,2) > 5),8);
else
test2(i,1)= {NaN};
end
end
dfcombin = [df3,test2];
1 comentario
Smithy
el 22 de Sept. de 2022
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