How to use a 'for loop' with inputs from the output of a previous equation.

2 visualizaciones (últimos 30 días)
Hello, Below is the code for inverse kinematics of a robot.
I wish to use the output of Theta [2x1] in for loop where value in first row and first colums of Theta is used in first iteration and value in 1st row and second column is used in second iteration.
I am new to Matlab.
gd=[-0.0256,-0.4496,-0.8929,-4.197;0.9758,0.1829,-0.1200,15.369;0.2173,-0.8743,0.4340,13.931;0,0,0,1];
gst0=[1 0 0 33; 0 1 0 -13; 0 0 1 14.7; 0 0 0 1];
g1=gd*inv(gst0);
p1=[24;-13;14.7];
p2=[0;-13;14.7];
r=[12;-13;0];
Delta=norm((g1*[p1;1])-[p2;1])
w4=[0;0;-1];
w=w4;
p=p1;
q=p2;
Theta=Thirdsubproblem (w,Delta,p,q,r)
for i=Theta(1,1):Theta(1:2)
w5=[0;0;-1];
w6=[1;0;0];
I=[1,0,0;0,1,0;0,0,1];
q4=[12;-13;14.7];
expOmega4hatTheta4=[cos(i),-sin(i),0;sin(i),cos(i),0;0,0,1];
expPsihat4Theta4=[expOmega4hatTheta4,((I-expOmega4hatTheta4)*q4);0,0,0,1];
p2=[0;-13;14.7];
p3=expPsihat4Theta4*[p2;1];
gd=[-0.0256,-0.4496,-0.8929,-4.197;0.9758,0.1829,-0.1200,15.369;0.2173,-0.8743,0.4340,13.931;0,0,0,1];
gst0=[1 0 0 33; 0 1 0 -13; 0 0 1 14.7; 0 0 0 1];
g2p2=inv(gd)*gst0*[p2;1];
q=p3([1,2,3],:);
p=g2p2([1,2,3],:);
w1=w5;
w2=w6;
r=[24;-13;14.7];
[Gamma]=Secondsubproblem (w1,w2,p,q,r)
for X=Gamma(1,1):Gamma(1:2)
u=p-r;
v=q-r;
alpha=((w1'*w2)*w2'*u-w1'*v)/(((w1'*w2)^2)-1);
Beta=((w1'*w2)*w1'*v-w2'*u)/(((w1'*w2)^2)-1);
z=(alpha*w1)+(Beta*w2)+(X)*(cross(w1,w2));
c=z+r;
Theta2SP2=Firstsubproblemsecond1 (w2,p,z,r)
Theta1SP1=Firstsubproblemsecond2 (w1,q,z,r)
clear
end
clear
end

Respuesta aceptada

Ghazwan
Ghazwan el 15 de Oct. de 2022
gd=[-0.0256,-0.4496,-0.8929,-4.197;0.9758,0.1829,-0.1200,15.369;0.2173,-0.8743,0.4340,13.931;0,0,0,1];
gst0=[1 0 0 33; 0 1 0 -13; 0 0 1 14.7; 0 0 0 1];
g1=gd*inv(gst0);
p1=[24;-13;14.7];
p2=[0;-13;14.7];
r=[12;-13;0];
Delta=norm((g1*[p1;1])-[p2;1])
w4=[0;0;-1];
w=w4;
p=p1;
q=p2;
Theta=Thirdsubproblem(w,Delta,p,q,r)
for ii=1:2
i=Theta(1,ii);
w5=[0;0;-1];
w6=[1;0;0];
I=[1,0,0;0,1,0;0,0,1];
q4=[12;-13;14.7];
expOmega4hatTheta4=[cos(i),-sin(i),0;sin(i),cos(i),0;0,0,1];
expPsihat4Theta4=[expOmega4hatTheta4,((I-expOmega4hatTheta4)*q4);0,0,0,1];
p2=[0;-13;14.7];
p3=expPsihat4Theta4*[p2;1];
gd=[-0.0256,-0.4496,-0.8929,-4.197;0.9758,0.1829,-0.1200,15.369;0.2173,-0.8743,0.4340,13.931;0,0,0,1];
gst0=[1 0 0 33; 0 1 0 -13; 0 0 1 14.7; 0 0 0 1];
g2p2=inv(gd)*gst0*[p2;1];
q=p3([1,2,3],:);
p=g2p2([1,2,3],:);
w1=w5;
w2=w6;
r=[24;-13;14.7];
[Gamma]=Secondsubproblem (w1,w2,p,q,r)
for jj=1:2
X=Gamma(1,jj);
u=p-r;
v=q-r;
alpha=((w1'*w2)*w2'*u-w1'*v)/(((w1'*w2)^2)-1);
Beta=((w1'*w2)*w1'*v-w2'*u)/(((w1'*w2)^2)-1);
z=(alpha*w1)+(Beta*w2)+(X)*(cross(w1,w2));
c=z+r;
Theta2SP2=Firstsubproblemsecond1 (w2,p,z,r)
Theta1SP1=Firstsubproblemsecond2 (w1,q,z,r)
clear
end
clear
end
  2 comentarios
Ghazwan
Ghazwan el 15 de Oct. de 2022
My pleasure. If my solution is correct, please mark "Accept this answer." Thank you.

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre Language Fundamentals en Help Center y File Exchange.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by