For example, I've got cell array:
c = {[10 12 13]' [4 5 6]' [7 8 9]';...
[10 20 30]' [40 5 60]' [70 80 90]';...
[100 200 300]' [400 500 600]' [3 800 9]' }
I need to find min in every row of c{i,j}, where i=j. So, I need to take c{1,1}, c{2,2}, c{3,3} and to find min of every row. I dont think my description is clear, so see the attached file. So the answer must be
ans = [3 5 9]'
Thanks a lot !

 Respuesta aceptada

Andrei Bobrov
Andrei Bobrov el 13 de Mzo. de 2015
Editada: Andrei Bobrov el 13 de Mzo. de 2015

0 votos

k = c(1:size(c,1)+1:end));% EDIT (diag(c));
or
k = c(eye(size(c))>0);
out = min([k{:}],[],2);

6 comentarios

Nik Zakh
Nik Zakh el 13 de Mzo. de 2015
Undefined function 'diag' for input arguments of type 'cell'
Andrei Bobrov
Andrei Bobrov el 13 de Mzo. de 2015
Editada: Andrei Bobrov el 13 de Mzo. de 2015
Sorry, I now use Octave... fixed.
Nik Zakh
Nik Zakh el 13 de Mzo. de 2015
It works ! Thanks ! Now I need to understand HOW does it work :)
Nik Zakh
Nik Zakh el 22 de Mzo. de 2015
Thanks for the previous answer ! Can you now help me to do the same thing, but for the case when i~=j ? Thanks !
Andrei Bobrov
Andrei Bobrov el 23 de Mzo. de 2015
variant
k = c(~eye(size(c)));
out = min([k{:}],[],2);
Nik Zakh
Nik Zakh el 23 de Mzo. de 2015
That's easy ! Thank you one more time !

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Más respuestas (1)

Jos (10584)
Jos (10584) el 23 de Mzo. de 2015

0 votos

min(cat(2,c{1:size(c,1)+1:end}),[],2)

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