Borrar filtros
Borrar filtros

how to avoid repeat numbers in a row

1 visualización (últimos 30 días)
imola
imola el 19 de Mzo. de 2015
Comentada: imola el 19 de Mzo. de 2015
Dear All,
I have this row
A=[1 2 3 4 5 6];
I tried to find random permutation on the vector but in many cases I got a row with repetition numbers for example
z=[1 5 2 4 1 5];or z=[1 5 2 4 1 1];
I want to avoid the repetition in this code but it is totally wrong, at first I should assign the missing numbers in such way, here is [3 6].
zc=[3 6 ];
e=size(zc,2);
z=[1 5 2 4 1 5];
for i=1:6
z(i)==z
s = find((z(i)==z) == 1)
ss=size(s,2);
for j=2:ss
for k=1:e
z(j)=zc(k)
end
end
end
I don't want to use a function from matlab to get the permutation, I need to fix my row or any permutation exchange file like (perm file ). If anyone help me for it and save me I will be grateful.
regards,
Imola
  2 comentarios
Guillaume
Guillaume el 19 de Mzo. de 2015
I don't want to use a function from matlab to get the permutation:
Does that mean that you've written your own uniform number generator? Otherwise, at some point you'll have to use rand, so you just might as well use randperm.
imola
imola el 19 de Mzo. de 2015
yes exactly I used randperm.

Iniciar sesión para comentar.

Respuesta aceptada

Sean de Wolski
Sean de Wolski el 19 de Mzo. de 2015
[~,x] = sort(rand(1,6))
No randperm
  1 comentario
imola
imola el 19 de Mzo. de 2015
I m sorry Sean,
but I wanted to accept Guillaume answer and by mistake I chose yours, how I change it because his answer was great.
regards

Iniciar sesión para comentar.

Más respuestas (1)

Guillaume
Guillaume el 19 de Mzo. de 2015
It seems to me that your effort would be better spent on fixing the code that generate these invalid permutation rather than fixing the permutation afterward.
Anyway, one way to do what you want:
z = [1 5 2 4 1 1];
zc = [3 6];
%build a cell array containing the indices of repeated values:
repindices = accumarray(z', 1:numel(z), [], @(v) {v(2:end)'})';
%convert cell array into vector:
repindices = [repindices{:}];
%replace values at indices by replacement:
z(repindices) = zc
  4 comentarios
Guillaume
Guillaume el 19 de Mzo. de 2015
If you're asking how to build zc:
zc = setdiff(1:6, z)
imola
imola el 19 de Mzo. de 2015
Dear Guillaume,
I'm so sorry, by mistake I chose Sean's answer. Forgave me.
Regards

Iniciar sesión para comentar.

Categorías

Más información sobre Creating and Concatenating Matrices en Help Center y File Exchange.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by