Cell conversion to double
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Steven
el 17 de Oct. de 2011
Editada: MathWorks Support Team
el 13 de Nov. de 2024 a las 4:01
Greetings, Let's say a is a 11x1 cell like this a = '0.000000' '1.000000' '2.000000' '3.000000' '4.000000' '5.000000' '6.000000' '7.000000' '8.000000' '9.000000' '10.000000' and I want to convert it in double. If I try b=cell2mat(a), I got the following error : ??? Error using ==> cat CAT arguments dimensions are not consistent. Error in ==> cell2mat at 85 m{n} = cat(1,c{:,n}); However, I know I can bypass it with a loop with 2 conversion as: for i = 1:length(a) b(i) = str2num(cell2mat(a(i))); end Thus, I wonder if there is a simpler way to do this with an easy one-step function. Regards, Steven
3 comentarios
ayesha abbassi
el 24 de Feb. de 2018
B = cell2mat(A). now check its type by writing whos B in command window
Chrysi K.
el 5 de Feb. de 2019
@ayesha abbassi Thank you so much!!! You helped me!!! I had a similar problem!
Respuesta aceptada
Jan
el 13 de Nov. de 2024 a las 0:00
Editada: MathWorks Support Team
el 13 de Nov. de 2024 a las 4:01
To convert a cell array of character vectors to numbers, you can use the |str2double| function. This function is the simplest method. C = {'0.000000'; '10.000000'; '100000.000000'}; M = str2double(C) The |cell2mat| function converts a cell array of character vectors to a character array, and only if all the character vectors have the same length. |cell2mat| also preserves the data type of the contents of the cells, so it does not convert characters to numbers. If you need your code to be fast, then use the following code instead. This code is faster than |str2double|: C = {'0.000000'; '1.000000'; '2.000000'; ... '3.000000'; '4.000000'; '5.000000'; '6.000000' '7.000000'; '8.000000'; '9.000000'; '10.000000'}; S = sprintf('%s*', C{:}); N = sscanf(S, '%f*'); Unfortunately |sprintf| seems to forget a proper pre-allocation. This C-Mex is 4 times faster: : S = CStr2String(C, '*'); N = sscanf(S, '%f*'); Timings in 2011b, Core2Duo: n = 100; C = cell(1, n); for iC = 1:n; C{i} = sprintf('%f', i); end tic; for i=1:1000; N = cellfun(@(x)str2double(x), C); end; toc >> 3.61 sec tic; for i=1:1000; N = cellfun(@(x) sscanf(x, '%f'), C); end; toc >> 3.01 sec tic; for i=1:1000; N = str2double(C); end; toc >> 2.79 sec tic; for i=1:1000; N = cellfun(@str2double, C); end; toc >> 2.49 sec tic; for i=1:1000; N = zeros(1,100); for j=1:100; N(j) = sscanf(C{j}, '%f'); end; end; toc >> 1.40 sec tic; for i=1:1000; N = sscanf(sprintf('%s*', C{:}), '%f*'); end; toc >> 0.14 sec tic; for i=1:1000; N = sscanf(CStr2String(C, '*'), '%f*'); end; toc >> 0.071 sec To my surprise a full implementation in C is *slower* than |sscanf(sprintf())|, see . Matlab's sscanf seems to be much better than the MSVC implementation.
9 comentarios
Giuseppe Degan Di Dieco
el 28 de Jun. de 2021
Dear Jan,
thanks for your tip. Still useful these days.
Best.
Hiril Patel
el 19 de Jun. de 2022
Hello Jan
i have cell of 73x1 of splitted data which i would like to convert to decimal but when I use M = str2double(adc_data). it returns to NaN
here is the string data i splitted
Más respuestas (1)
Daniel Shub
el 17 de Oct. de 2011
It appears your cell array contains strings and not numbers (doubles).
b = cellfun(@(x)str2double(x), a);
6 comentarios
Fangjun Jiang
el 17 de Oct. de 2011
+1, For none-time-critical task, I still vote for using str2double().
hello_world
el 4 de Jul. de 2018
@Daniel Shub: It converts all cell entries (which are string) into NaN values. I have raised a question at: https://www.mathworks.com/matlabcentral/answers/408675-how-to-convert-a-csv-file-of-cell-array-type-to-double
Can you please look into that?
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