Subtracting a value in a 3D array with all values in another 3D array

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Hello, I have 2 three-dimensional arrays, i would like to take the first value in the first array and subtract it with all values in the second array, and then the second value in the first array with all values in the second array, and in each time the smallest value of the subtraction is put in a new array.
Thank you in advance
  2 comentarios
Matt J
Matt J el 26 de Nov. de 2022
Editada: Matt J el 26 de Nov. de 2022
What are the sizes of the arrays?
Does "smallest" mean min(x-y) or min(abs(x-y))?

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Jan
Jan el 26 de Nov. de 2022
Editada: Jan el 26 de Nov. de 2022
A = rand(5,6,7);
B = rand(6,7,8);
D = min(A(:).' - B(:), [], 1);
Result = reshape(D, size(A));
If the intermediate matrix A(:).'-B(:) exhausts the available RAM, use a loop:
Result = zeros(size(A));
for k = 1:numel(A)
Result(k) = min(A(k) - B, [], 'all');
end
  2 comentarios
Sarah Bassiouny
Sarah Bassiouny el 26 de Nov. de 2022
okay perfect, i got the results of the smallest value, now i need to know the position of that value and display it in the form of an array, so if the smallest value is in position 4 then the value in the results matrix is the difference, and the array is 6.
Thank you in advance
Jan
Jan el 27 de Nov. de 2022
[D, Pos] = min(A(:).' - B(:), [], 1);
determines the position also as linear index. But what do you exactly need as output "position" for 3D arrays?
I do not understand, what this means: "if the smallest value is in position 4 then the value in the results matrix is the difference, and the array is 6." Why 6?

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