Resampling matrices in a loop using interp2

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Dinuka Kankanige
Dinuka Kankanige el 3 de Dic. de 2022
Comentada: Star Strider el 12 de Dic. de 2022
I'm trying to resample 200 matrices of 300*500 size to 30*50 using interp2. My objective is to load each resampled matrix into workspace after running the loop. In the code given here, it indicates there's an issue with how I use interp2 within the for-loop. Could someone please help me resolve this? Or any better approaches than this are also welcome.
-Thank you-
%filepath to directory where data is located
filepath='C:\Users\Task 1\';
%root part of filename (part that doesn't change each time)
filestem='VOD_Au_0dot1degree_';
for i=1:200
%loading files into a struct
A(i)=load(strcat(filepath,filestem,num2str(i),'.mat'));
%resampling
%new matrix column & row size
nc=50;nr=30;
%current matrix column & row size
c=500;r=300;
[C,R]=meshgrid(1:(c-1)/(nc-1):c,1:(r-1)/(nr-1):r);
downscaled_vod(i)=interp2(double(A(i).vod_monthly),C,R);
figure(i)=imagesc(downscaled_vod(i));
end

Respuesta aceptada

Star Strider
Star Strider el 3 de Dic. de 2022
I am not certain what hte problem is, since the error messagd is not part of the provided information.
I suspect the problem is in saving a matrix to a scalar, defined by:
downscaled_vod(i)
That can be solved by saving it to a cell array element:
downscaled_vod{i}
The same sort of problem could be due to the ‘double(A(i).vod_monthly)’ reference, although without more information, I cannot determine that.
A = exp(-((1:300).'-150).^2/3000) * exp(-((1:500)-250).^2/5000); % Create Matrix To Be Interpolated
figure
surf(A, 'EdgeColor','none')
colormap(turbo)
title('Original')
i = 1;
nc=50;
nr=30;
c=500;
r=300;
rv = linspace(1,r,nr);
cv = linspace(1,c,nc);
[C,R] = meshgrid(cv, rv);
downscaled.vod{i} = interp2(A, C, R);
figure
surf(downscaled.vod{i})
colormap(turbo)
title('Downscaled')
Using linspace to create the interpolation vectors is likely more efficien than the current code.
Also, put all these:
nc=50;
nr=30;
c=500;
r=300;
rv = linspace(1,r,nr);
cv = linspace(1,c,nc);
[C,R] = meshgrid(cv, rv);
before the loop, because they don't change in loop iterations. There is no need to create them in each iteration.
.
  2 comentarios
Dinuka Kankanige
Dinuka Kankanige el 12 de Dic. de 2022
Thank you. This is helpful.
Star Strider
Star Strider el 12 de Dic. de 2022
As always, my pleasure!

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Más respuestas (1)

Matt J
Matt J el 3 de Dic. de 2022
Movida: Matt J el 3 de Dic. de 2022
It is wasteful here to use meshgrid. Also, you should hoist C and R out of the the loop since they don't change with i:
%resampling
%new matrix column & row size
nc=50;nr=30;
%current matrix column & row size
c=500;r=300;
[C,R]=deal(1:(c-1)/(nc-1):c,1:(r-1)/(nr-1):r);
for i=1:200
%loading files into a struct
A(i)=load(strcat(filepath,filestem,num2str(i),'.mat'));
downscaled_vod{i}=interp2(double(A(i).vod_monthly),C,R);
figure(i)=imagesc(downscaled_vod{i});
end

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