How can I generate a pseudo random column vector V

for N = [1 2 5 10.^[ 1 : 5 ] ]
    V = rand( N, 1 ) ; % I'm not sure if it should look like this
end

I have this cycle, how can I generate a pseudo random column vector V of varying length N (using this cycle)

Answer 1

[Jon]

Yes this will make a random column vector of length N at each iteration.

The values will be uniformly distributed between 0 and 1. If you want them normally distributed use randn.

[Ihor]

Thank you!

[Jon]

Glad that helped. If that answered your question please accept the answer so that others who might have a similar problem will know that an answer is available.