please anyone convert this c++ code into MATLAB

#include<stdio.h>

         #include<iostream.h>
         #include<conio.h>
         #include<string.h>
         void main()
         {
         int i,j,cnt,l,count[50];
         char str[50];
         clrscr();
         printf("Enter the string");
         scanf("%s",str);
         printf("\n\t original s]==string is:%s",str);
         printf("\n\n\t encoded string is:");

         for(i=0;i<l;i=i*1)
         {
         j=0;
         count[i]=1;
         do
         {
         j++;
         if(str[i+j]==str[i])
         count[i]++;
         }
         while(str[i+j]==str[i]);

         if(count[i]==1)
         printf("%c",str[i++]);
         else
         {
         printf("%c%d",str[i],count[i]);
         i=i+count[i];
         }
         }

getch();
         }

[Stephen23]

Please do not post duplicate questions:

http://it.mathworks.com/matlabcentral/answers/186725-can-anyone-tell-me-how-to-convert-this-do-while-loop-of-c-to-matlab-expression

[James Tursa]

for(i=0;i<l;i=i*1)

In the above line, you use variable l before it is defined. Is l supposed to be the length of the string str?

Also, the last part of this for construct is i=i*1, which will essentially do nothing. Is this intended? If you want to do nothing here, then typically one would leave that part blank rather than put in code that accomplishes nothing.

Answer 1

[James Tursa]

Making assumption that l is the string length (a really BAD choice for a variable name btw), here is a fairly literal translation. The functionality appears to simply count repeated letters and put that count into the output string, so this whole thing could probably be rewritten using that knowledge (but I am not going to do that for you here).

function estring(str)
l = numel(str);
i = 0;
count = zeros(1,l);
while( i < l )
    j=0;
    count(i+1) = 1;
    while( true )
        j = j + 1;
        if( i+j+1 > l )
            break;
        end
        if( str(i+j+1)==str(i+1) )
            count(i+1) = count(i+1) + 1;
        else
            break;
        end
    end
    if( count(i+1)==1 )
        fprintf('%c',str(i+1)); i = i + 1;
    else
        fprintf('%c%d',str(i+1),count(i+1));
        i = i + count(i+1);
    end
end
fprintf('\n');
end

E.g.,

>> estring('abcdef')
abcdef
>> estring('aabbbcdeeeeef')
a2b3cde5f
>> estring('abcccdefggggggggggggggggggggg')
abc3defg21