How to write a while loop that returns the number of the value you put in?

Hello, so the title might be confusing and i'll try to explain it better. I want to create a while loop so if the user put in the number let's say 4575, it'll return the number 4. Or 893 and itll return the number 3, 78 and itll return number 2 and so forth. Absolutely clueless on how to solve this honestly

[Stephen23]

"Absolutely clueless on how to solve this honestly"

Some people will tell you to convert to text, but the real solution is to use mathematics: what does LOG10 give you?

Try it, and show us what you come up with.

Answer 1

[Image Analyst]

Have the user put in the number as a string with input

userInput = input('Enter your number : ', 's');
fprintf('Your number of %s is %d digits long.\n', userInput, length(userInput));

Not sure how a while loop comes into play. Do you want that in a while loop and keep asking them unless they type quit or something? Like this:

userInput = 'a';
while ~startsWith(userInput, 'Q', 'IgnoreCase',true)
    userInput = input('Enter your number (Q to quit): ', 's');
    if startsWith(userInput, 'Q', 'IgnoreCase',true)
        break
    end
    fprintf('Your number of %s is %d digits long.\n', userInput, length(userInput));
end

[Tess]

ahhh i absolutely appreciate it, very helpful thank you !

[Image Analyst]

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Answer 2

[Jan]

x = [4575, 893, 78, 12345];
y = floor(log10(x) + 1)

y = 1×4

4 3 2 5

Do you really need a loop?

x = 10000;
n = 0;
while x >= 1
    n = n + 1;
    x = x / 10;
end
n

n = 5

[Saleh]

jan thank you very much for helping me in my course really you helped me aloy i appreciate it <3 <3 <3 <3 <3

[Tess]

thank you, appreciate it man !

[Walter Roberson]

Watch out for 0 and negative numbers.