How to get the 1×1 cell array?

hello, everybody

I would like to get the 1×1 cell array of {'m, -10, -15, L -4.7, 0 c 0, 0'}.

some values are caluclated from the variables.

I tried with str = {'m, offset+pos, offset+neg, L -neg+0.3, 0 c 0, 0'}.

However, the answer is {'m, offset+pos, offset+neg, L -neg+0.3, 0 c 0, 0'}.

it is just string and no calculation of variables.

I also tried with str = {"m", offset+pos, offset+neg, "L" -neg+0.3, 0 "c" 0, 0};

There is calculation of variables, However, it is 1×9 cell array.

How to get the 1×1 cell array of {'m, -10, -15, L -4.7, 0 c 0, 0'}?

offset = -20;

pos = 10;

neg = 5;

% str = {'m, offset+pos, offset+neg, L -neg+0.3, 0 c 0, 0'}; % just string and no calculation of variables

% str = {"m", offset+pos, offset+neg, "L" -neg+0.3, 0 "c" 0, 0}; % it is 1×9 cell array

% output I want is : 1×1 cell array of {'m, -10, -15, L -4.7, 0 c 0, 0'}

% str = {'m, -10, -15, L -4.7, 0 c 0, 0'};

[Stephen23]

The best approach is to either use SPRINTF, just as Voss shows here:

https://www.mathworks.com/matlabcentral/answers/1887597-how-to-get-the-1x1-cell-array#answer_1140062

or the new overloaded STRING operators, e.g.:

offset = -20;
pos = 10;
neg = 5;
str = "m, "+(offset+pos)+","+(offset+neg)+" L "+(-neg+0.3)+", 0 c 0, 0"

str = "m, -10,-15 L -4.7, 0 c 0, 0"

Answer 1

[KSSV]

offset = -20;
pos = 10;
neg = 5;
str = {['m, ', num2str(offset+pos),',', num2str(offset+neg), ' L ', num2str(-neg+0.3),',', '0 c 0, 0']};  % just string and no calculation of variables
str

str = 1×1 cell array
    {'m, -10,-15 L -4.7,0 c 0, 0'}

[Smithy]

Wow.. Thank you very much~!!! It works really well. I really really appreciate with it.

Answer 2

[Voss]

offset = -20;
pos = 10;
neg = 5;

str = {sprintf('m, %g, %g, L -%g, 0 c 0, 0',offset+pos,offset+neg,neg-0.3)}

str = 1×1 cell array
    {'m, -10, -15, L -4.7, 0 c 0, 0'}

[Smithy]

Thank you very much. It works well. Wonderful.