I need help to make graphs please
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Hello! I have the following program 1 that depends on subroutines 2,3 and 4 I need to graph [flux(index) vs w] and also [Q_t(j) vs d] can someone help me? The graphs should be on a logarithmic scale on both axes.
program 1)
clear all
clc
tic
h = 1.054571596e-34;
global c0;
c0 = 2.99792458e+8;
kb = 1.3806503e-23;
qe = 1.602176462e-19;
e0 = 8.854187817e-12;
T1 = 300;
T2 = 299;
dc = 0.5e-9;
beta_max = pi/dc;
darray = [1e-8, 1e-7, 1e-6];
w1 = 2e12;
w2 = 2e15;
dw = 2e12;
nw = floor((w2-w1)/dw+1);
for j = 1:length(darray)
d=darray(j);
index=0;
for w=w1:dw:w2;
ep1=Lorentz_SiC(w);
ep2=Lorentz_SiC(w);
index = index+1;
a0 = 0;
a1 = (w-10)/c0;
nkp = 1000;
errp = 0.01;
ae1 = (w+10)/c0;
ae2 = 8*w/c0;
ae3 = 100*w/c0;
ae4 = beta_max;
nke0 = 1000;
nke1 = 1000;
nke2 = 1000;
erre0 = 1.0;
erre1 = 0.01;
erre2 = 0.1;
Q1=h*w/(exp(h*w/(kb*T1))-1);
Q2=h*w/(exp(h*w/(kb*T2))-1);
val_p = simpson_p(w, nkp, d, a0, a1, ep1, ep2, errp);
fluxp=val_p*(Q1-Q2);
val_e0= simpson_e(w, nke0, d, ae1, ae2, ep1, ep2, erre0);
fluxe0=val_e0*(Q1-Q2);
val_e1= simpson_e(w, nke1, d, ae2, ae3, ep1, ep2, erre1);
fluxe1=val_e1*(Q1-Q2);
val_e2= simpson_e(w, nke2, d, ae3, ae4, ep1, ep2, erre2);
fluxe2=val_e2*(Q1-Q2);
flux(j,index)=fluxp+fluxe0+fluxe1+fluxe2;
end
Q_t(j)=(flux(1)+4*sum(flux(2:2:(nw-1)))+2*sum(flux(3:2:(nw-2)))+flux(nw))*dw/3;
end
figure(1)
plot(darray,Q_t)
figure(2)
plot(w1:dw:w2,flux)
-----------------------------------------------------------------------------------------------------------------
subroutine 2
function [e_1] = Lorentz_SiC(w)
wL = 1.82652e+14;
wT = 1.49477e+14;
gamma = 8.9724e+11;
e_inf = 6.7;
e_1 = e_inf*(1+(wL*wL-wT*wT)./(wT*wT-w.*w-i*gamma*w));%1-wp*wp/(w*w+i*w*gal);
end
-------------------------------------------------------------------------------------------------------------------
subroutine 3
function [Int_val] = simpson_p(w, n, d, min, max, ep_1, ep_2, err)
n1 = n;
[s_p,dkx] = func_p(w, n1, d, min, max, ep_1, ep_2);
temp1=(s_p(1)+4*sum(s_p(2:2:n1))+2*sum(s_p(3:2:n1-1))+s_p(n1+1))*dkx/3;
if(temp1<=1e-50)
temp2 = 0;
else
n1 = n1*2;
[s_p,dkx] = func_p(w, n1, d, min, max, ep_1, ep_2);
temp2=(s_p(1)+4*sum(s_p(2:2:n1))+2*sum(s_p(3:2:n1-1))+s_p(n1+1))*dkx/3;
while ((abs(temp2-temp1)/temp2) >= err)
temp1 = temp2;
n1 = n1*2;
[s_p,dkx] = func_p(w, n1, d, min, max, ep_1, ep_2);
temp2=(s_p(1)+4*sum(s_p(2:2:n1))+2*sum(s_p(3:2:n1-1))+s_p(n1+1))*dkx/3;
end
end
Int_val = temp2;
end
function [s_p,dkx] = func_p(w, n, d, min, max, ep_1, ep_2)
global c0
dkx = (max-min)/n;
kx = zeros(n+1,1);
s_p = zeros(n+1,1);
for ind=1:n+1
kx(ind)= min+(ind-1)*dkx;
kz1 = sqrt(ep_1*w*w/(c0*c0)-kx(ind)^2);
kz2 = sqrt(ep_2*w*w/(c0*c0)-kx(ind)^2);
kz3 = sqrt(w*w/(c0*c0)-kx(ind)^2);
rs31 = ((kz3-kz1)/(kz3+kz1));
rp31 = ((ep_1*kz3-kz1)/(ep_1*kz3+kz1));
rs32 = ((kz3-kz2)/(kz3+kz2));
rp32 = ((ep_2*kz3-kz2)/(ep_2*kz3+kz2));
tps_temp = abs(1-rs31*rs32*exp(2*i*kz3*d));
tpp_temp = abs(1-rp31*rp32*exp(2*i*kz3*d));
s_p(ind) = kx(ind)*((1-abs(rs31)^2)*(1-abs(rs32)^2)/tps_temp^2+(1-abs(rp31)^2)*(1-abs(rp32)^2)/(tpp_temp^2))/(4*pi*pi);
end
end
----------------------------------------------------------------------------------------------------------
subroutine 4
function [Int_val] = simpson_e(w, n, d, min, max, ep_1, ep_2, err)
n1 = n;
[s_e,dkx] = func_e(w, n1, d, min, max, ep_1, ep_2);
temp1=(s_e(1)+4*sum(s_e(2:2:n1))+2*sum(s_e(3:2:n1-1))+s_e(n1+1))*dkx/3;
if(temp1<=1e-50)
temp2 = 0;
else
n1 = n1*2;
[s_e,dkx] = func_e(w, n1, d, min, max, ep_1, ep_2);
temp2=(s_e(1)+4*sum(s_e(2:2:n1))+2*sum(s_e(3:2:n1-1))+s_e(n1+1))*dkx/3;
while ((abs(temp2-temp1)/temp2) >= err)
temp1 = temp2;
n1 = n1*2;
[s_e,dkx] = func_e(w, n1, d, min, max, ep_1, ep_2);
temp2=(s_e(1)+4*sum(s_e(2:2:n1))+2*sum(s_e(3:2:n1-1))+s_e(n1+1))*dkx/3;
end
end
Int_val = temp2;
end
function [s_e,dkx] = func_e(w, n, d, min, max, ep_1, ep_2)
global c0
dkx = (max-min)/n;
kx = zeros(n+1,1);
s_e = zeros(n+1,1);
for ind=1:n+1
kx(ind)= min+(ind-1)*dkx;
kz1 = sqrt(ep_1*w*w/(c0*c0)-kx(ind)^2);
kz2 = sqrt(ep_2*w*w/(c0*c0)-kx(ind)^2);
kz3 = sqrt(w*w/(c0*c0)-kx(ind)^2);
rs31 = ((kz3-kz1)/(kz3+kz1));
rp31 = ((ep_1*kz3-kz1)/(ep_1*kz3+kz1));
rs32 = ((kz3-kz2)/(kz3+kz2));
rp32 = ((ep_2*kz3-kz2)/(ep_2*kz3+kz2));
e_temp = exp(-2*imag(kz3)*d);
s_e(ind) = kx(ind)*e_temp*(imag(rs31)*imag(rs32)/(abs(1-rs31*rs32*e_temp))^2+imag(rp31)*imag(rp32)/(abs(1-rp31*rp32*e_temp))^2)/(pi*pi);
end
end
Respuesta aceptada
Más respuestas (1)
Constantino Carlos Reyes-Aldasoro
el 3 de En. de 2023
0 votos
It is easier to help for specific questions, i.e., you tried something and it did not work. The way you have phrased this is more like trying to solve your homework and you will not get much help.
1 comentario
Yordani
el 3 de En. de 2023
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