How to figure a colour based on a matrice of 1-by-3
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This is my code:
%%In this part we just find the coordinates of the required colours
im = imread('Lighthouse.jpg');
n = 4;
figure, imshow(im)
[x,y] = ginput(n);
x = floor(x);
y = floor(y);
%colour(length(x),3);
for i=1:length(x)
for j=1:3
colour(i,j) = im(y(i),x(i),j);
end
end
image(colour)
when I run it, and slect a point on the image it doesn't show me the colour I selected!! it figures a red colour!! why is that? the variable colour is [195,213,223]
how can I visualize that RGB colour?
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Respuesta aceptada
Image Analyst
el 20 de Oct. de 2011
Well you messed up in a couple of places. Try this:
im = imread('peppers.png');
n = 4;
figure, imshow(im)
[x,y] = ginput(n);
x = floor(x);
y = floor(y);
%colour(length(x),3);
colour = zeros(length(x), 1, 3, 'uint8');
for i=1:length(x)
for j=1:3
colour(i,1, j) = im(y(i),x(i),j);
end
end
image(colour)
Más respuestas (2)
the cyclist
el 20 de Oct. de 2011
Divide by 255. MATLAB uses the convention of RGB values from (0,1). This was discussed on this forum a few weeks ago, but for some reason I can't find it.
Walter Roberson
el 20 de Oct. de 2011
Before the loop, initialize
colour = zeros(length(x),3, 'uint8');
You will then not need to do the division by 255 that The Cyclist refers to.
2 comentarios
Walter Roberson
el 20 de Oct. de 2011
You are selecting 4 points so you should be getting 4 colors.
You need to check whether your file is RGB (truecolor) or an indexed image (2D but you have to read in the colormap as well.)
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