Getting Error while using Transparency to object (alpha)
3 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Telema Harry
el 13 de En. de 2023
Comentada: Telema Harry
el 14 de En. de 2023
I get the following error ("Unable to use a value of type matlab.graphics.chart.primitive. Surface as an index. alpha(s,.2)") message sometimes and I don't know why?
r = 50; % The radius of the circular plan given in Km
r = km2deg(r); % Convert to Degree
[X,Y,Z] = cylinder(r);
p0=[48,278,0]; % base location in Degrees
X=X+p0(1); Y=Y+p0(2); Z=Z+p0(3); %translate cylinder to new location
h = 80;
Z = Z*h;
subplot(2, 2, [1 3])
s = surf(Y,X,Z,'FaceColor','#80B3FF', 'EdgeColor','none');
% view(43,180);
% camdolly(0,0,0)
alpha(s,.2)
I am using MATLAB R2022a on a macOS ventura 13.1 machine.
0 comentarios
Respuesta aceptada
Más respuestas (0)
Ver también
Categorías
Más información sobre Lighting, Transparency, and Shading en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!