Create a random Matrix
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I have a 8 column vector n*1. Can I create a Random matrix of n*8?
The function must take one value from each vector and create a matrix with 8 columns and n rows.
Please help me :-)
2 comentarios
Jan
el 24 de Oct. de 2011
"I have a 8 column vector" sounds like a single vector. But "from each vector" might mean n vectors. Confusing.
Respuesta aceptada
Andrei Bobrov
el 24 de Oct. de 2011
A1,A2,..,A8 - your vectors (nx1), let n = 5;
for j1 = 1:8, eval([sprintf('A%d',j1),'=randi(20,5,1)']); end
A = eval(['[',sprintf('A%d,',1:8),']'])
out=A(bsxfun(@plus,cell2mat(arrayfun(@(x)randperm(n)',(1:8),'un',0)),(0:7)*n))
3 comentarios
Jan
el 31 de Oct. de 2011
@Maurizio: Accepting an answer means, that it solves your problem sufficiently.
Más respuestas (1)
Walter Roberson
el 24 de Oct. de 2011
rv(:,1) = randomvector1;
rv(:,2) = randomvector2;
rv(:,3) = randomvector3;
....
rv(:,4) = randomvector4;
rants = zeros(8, n);
for K = 1:n
rants(:,K) = A Random Selection of One Entry Per Column from rv
end
How to do "A Random Selection of One Entry Per Column from rv" is left to you to work on in more detail. I will hint that it involves using rand().
3 comentarios
Walter Roberson
el 30 de Oct. de 2011
floor(1 + n * rand())
will give you a random row number.
If I say much more than I will be completing your assignment for you.
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