how run generated code from apps
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roberto
el 16 de Feb. de 2023
hello everybody
I've generated a simple code from curve fitting app by export code toolbar.
I've tried to past it in command windows but doesn't work.
function [fitresult, gof] = createFit(close)
%CREATEFIT(CLOSE)
% Create a fit.
%
% Data for 'untitled fit 1' fit:
% Y Output: close from eurusd
% Output:
% fitresult : a fit object representing the fit.
% gof : structure with goodness-of fit info.
%
% See also FIT, CFIT, SFIT.
% Auto-generated by MATLAB on 16-Feb-2023 15:06:52
%% Fit: 'untitled fit 1'.
[xData, yData] = prepareCurveData( [], close );
% Set up fittype and options.
ft = fittype( 'poly1' );
% Fit model to data.
[fitresult, gof] = fit( xData, yData, ft );
% Plot fit with data.
figure( 'Name', 'untitled fit 1' );
h = plot( fitresult, xData, yData );
legend( h, 'close', 'untitled fit 1', 'Location', 'NorthEast', 'Interpreter', 'none' );
% Label axes
ylabel( 'close', 'Interpreter', 'none' );
grid on
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Respuesta aceptada
Kevin Holly
el 16 de Feb. de 2023
Editada: Kevin Holly
el 16 de Feb. de 2023
You would want to save the code as a .m file. Then you can call the function with this line:
createFit(close)
Where close is your input
For example:
data = rand(14,1);
createFit(data)
function [fitresult, gof] = createFit(close)
%CREATEFIT(CLOSE)
% Create a fit.
%
% Data for 'untitled fit 1' fit:
% Y Output: close from eurusd
% Output:
% fitresult : a fit object representing the fit.
% gof : structure with goodness-of fit info.
%
% See also FIT, CFIT, SFIT.
% Auto-generated by MATLAB on 16-Feb-2023 15:06:52
%% Fit: 'untitled fit 1'.
[xData, yData] = prepareCurveData( [], close );
% Set up fittype and options.
ft = fittype( 'poly1' );
% Fit model to data.
[fitresult, gof] = fit( xData, yData, ft );
% Plot fit with data.
figure( 'Name', 'untitled fit 1' );
h = plot( fitresult, xData, yData );
legend( h, 'close', 'untitled fit 1', 'Location', 'NorthEast', 'Interpreter', 'none' );
% Label axes
ylabel( 'close', 'Interpreter', 'none' );
grid on
end
2 comentarios
Kevin Holly
el 16 de Feb. de 2023
Please accept the answer if this satisfies your questions. Thanks.
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