solve system of matrices
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% I want to solve this system
f'(A,B)*[dA dB]'=[g(C))+B B*A-eye(n-1)]'
but when I found the derivative of f in the left side, I found that
f'(A,B)*[dA dB]'= [g(dA))-dB A*dB+B*dA]'
where A,B are (n-1)×(n-1) matrices
and C is n×n matrices
and I define a function chi from (n-1)×(n-1) matrices to the n×n matrices as
function chi= g(X)
chi= 3*trace X;
end
I want to solve this system for dA and dB
the problem for me is in the derivative part here
f'(A,B)*[dA dB]'= [g(dA))-dB A*dB+B*dA]'
can I said
[g(dA))-dB A*dB+B*dA]'= [g -eye(n-1);B A]*[dA dB]'
if not can I solve this system for dA and dB if i write it as
[g(dA)-dB A*dB+B*dA]'=[g(C)+B B*A-eye(n-1)]'
9 comentarios
Torsten
el 17 de Feb. de 2023
As far as I understand your question, you want - given A, B and C - determine dA and dB both matrices of size
(n-1) x (n-1) such that
[g(dA)-dB A*dB+B*dA]'=[g(C)+B B*A-eye(n-1)]'
where g is defined as
g(M) = 3*trace(M)
A,B are matrices of size (n-1) x (n-1) and C is a matrix of size n x n.
Is this correct ?
Hajar Alshaikh
el 17 de Feb. de 2023
Torsten
el 17 de Feb. de 2023
Then transform your matrix equation to the form
M*x = b
by using MATLAB's "equationsToMatrix" and solve for the unknown matrices dA and dB using
x = M\b.
Hajar Alshaikh
el 17 de Feb. de 2023
Torsten
el 18 de Feb. de 2023
The matrix equation you have is in reality a linear system of equations in the matrix entries of dA and dB.
"equationsToMatrix" transforms your matrix equation to this underlying linear system.
After getting the solution x of this linear system, you will have to reshape it back to get the matrices dA and dB.
Hajar Alshaikh
el 18 de Feb. de 2023
So this is not what you want ?
rng("default")
n = 20;
A = rand(n-1);
B = rand(n-1);
C = rand(n-1);
dA = sym('dA',[n-1 n-1],'real');
dB = sym('dB',[n-1 n-1],'real');
eqn = [3*trace(dA)-dB A*dB+B*dA]'==[3*trace(C)+B B*A-eye(n-1)]';
eqn = eqn(:);
vars = [reshape(dA.',[(n-1)^2 1]);reshape(dB.',[(n-1)^2 1])];
[M,b] = equationsToMatrix(eqn,vars);
sol = double(M\b);
dA = reshape(sol(1:(n-1)^2),[n-1 n-1]).';
dB = reshape(sol((n-1)^2+1:2*(n-1)^2),[n-1 n-1]).';
[3*trace(dA)-dB A*dB+B*dA]'-[3*trace(C)+B B*A-eye(n-1)]'
Hajar Alshaikh
el 18 de Feb. de 2023
Torsten
el 18 de Feb. de 2023
My example worked - so I cannot tell you what went wrong with your code.
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