solve equation for a variable

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SETH SCHREINER
SETH SCHREINER el 28 de Feb. de 2023
Comentada: Anton Kogios el 28 de Feb. de 2023
I'm sure this sort of thing has been posted numerous times, but I can't find anything that works for me for whatever reason. I need to solve an equation for a variable, and I can't remember how to do this. It's been a while since I've used matlab. I need to solve for t numerically. This is the last thing I tried:
v = 2.42;
si_f235 = 577E-24;
N_235 = 780.63E18;
phi = 3E13;
si_a235 = 101E-24;
si_a238 = 2.73E-24;
N_238 = 21.52E21;
n = 1.5;
eqn = @(x) v*si_f235*N_235(1-si_f235*phi*x)/(si_a235*N_235*(1-si_a235*phi*x)+si_a238*N_238*(1-si_a238*phi*x))==n;
t = vpasolve(eqn , x)
it's just telling me that x is an unrecognized variable

Respuesta aceptada

Anton Kogios
Anton Kogios el 28 de Feb. de 2023
This works for me (you were also missing an * in your equation):
v = 2.42;
si_f235 = 577E-24;
N_235 = 780.63E18;
phi = 3E13;
si_a235 = 101E-24;
si_a238 = 2.73E-24;
N_238 = 21.52E21;
n = 1.5;
syms x
eqn = v*si_f235*N_235*(1-si_f235*phi*x)/(si_a235*N_235*(1-si_a235*phi*x)+si_a238*N_238*(1-si_a238*phi*x))==n;
t = vpasolve(eqn , x)
t = 
47756908.067411697270732667471209
  3 comentarios
SETH SCHREINER
SETH SCHREINER el 28 de Feb. de 2023
oh i dont have the right toolbox apparently
Anton Kogios
Anton Kogios el 28 de Feb. de 2023
Yes sorry, this requires the Symbolic Math Toolbox, which is very helpful for these sorts of problems. You could of course always follow Torsten's advice in his answer.

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Más respuestas (1)

Torsten
Torsten el 28 de Feb. de 2023
Editada: Torsten el 28 de Feb. de 2023
You don't need a toolbox for this.
Take a piece of paper and a pencil, multiply the equation by the denominator of the left-hand side, collect terms with x on one side and other terms on the other side, factor out x on the one side and solve for x.
It's just like solving 3*x + 5 = 7*x - 4 for x.
  1 comentario
SETH SCHREINER
SETH SCHREINER el 28 de Feb. de 2023
I get how to do it on pencil and paper, but the equation gets rather tedious trying to separate out x from the other variables towards the end

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