Hello, how can I calculate the row and column by inserting a 3D matrix using this equation

clc
clear all
close all
xm= [5 5 5 5;5 -4 -3 -2;5 -1 0 1;5 2 3 4]

xm = 4×4

5 5 5 5 5 -4 -3 -2 5 -1 0 1 5 2 3 4

n=length(xm);
[cf] =coherence_factor(xm,n)

cf = 1×4

1.0000 0.0741 0.2315 0.9074

function [cf] = coherence_factor(xm,n)
for i=1:4;
    n=length(xm(i,:));
    %%%%%%%%%%%%%%%%%%%%  equation  %%%%%%%%%%%%%%%%%%%
    cf(i)=(abs (sum(xm(i,:))).^2) / (n* sum(abs(xm(i,:).^2)));
end
CF=cf(i);
end

[Torsten]

Could you explain in more detail what you want to do ?

The code above works - what needs to be changed ?

[hisham mohammed]

I want to add another forloop to calculate 3D matrix of CF

[Jan]

@hisham mohammed: You define n as input argument, but overwrite it by the same value in each iteration. Of course all xm(i,:) have the same length. So use this before the loop:

m = size(xm, 2);

The line CF=cf(i); is useless, because CF is not replied. Currently the output is a vector. It is not clear how you want to expand ot to 3D.