How to take an average from range of values?

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Haya Ali
Haya Ali el 17 de Mzo. de 2023
Comentada: Dyuman Joshi el 17 de Mzo. de 2023
I have this array and according to excel histogram plot the mostly values are located in the range [-0.5,0.5]. I want to sort all values from the array A that lies in this range and take there average. How can I do this?
A= [0.0000 0.4341 -0.0000 -0.5910 -0.0352 2.0350 -0.0000 -0.9597 0.0000 -1.2164 -2.7826 -0.0000 0.3716 -0.0000 -0.0000 -0.0000 1.4557 0.0000 -0.0000 0.5599 -0.0000 -0.2463 -0.7001 0.0000]

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Dyuman Joshi
Dyuman Joshi el 17 de Mzo. de 2023
It seems you have copied the data from Excel and there is a loss of data in doing that.
A= [0.0000 0.4341 -0.0000 -0.5910 -0.0352 2.0350 -0.0000 -0.9597 0.0000 -1.2164 -2.7826 -0.0000 0.3716 -0.0000 -0.0000 -0.0000 1.4557 0.0000 -0.0000 0.5599 -0.0000 -0.2463 -0.7001 0.0000];
%range
idx = A>=-0.5 & A<=0.5;
%sorted A values in the range
B = sort(A(idx))
B = 1×16
-0.2463 -0.0352 0 0 0 0 0 0 0 0 0 0 0 0 0.3716 0.4341
avg = mean(B)
avg = 0.0328
Note that the range containing maximum number of elements can vary according to the bin size and the start point.
For example -
%bin size 0.5, start point -3.5, the range [0 0.5] has the max no. of elements
bin=-3.5:0.5:3.5;
histogram(A,bin)
xticks(bin)
%bin size - 0.3, start point -3.2, range with max elements is [-0.2 0.1]
bin=-3.2:0.3:3;
histogram(A,bin)
xticks(bin)
  2 comentarios
Haya Ali
Haya Ali el 17 de Mzo. de 2023
Is this a way to find a range also in which most values lies?
Dyuman Joshi
Dyuman Joshi el 17 de Mzo. de 2023
It will depend upon the size and the starting point of the range, as I said above.
Let's say the bin size is 0.5, and the starting and end points are -3 and 3 respectively
A = [0.0000 0.4341 -0.0000 -0.5910 -0.0352 2.0350 -0.0000 -0.9597 0.0000 -1.2164 -2.7826 -0.0000 0.3716 -0.0000 -0.0000 -0.0000 1.4557 0.0000 -0.0000 0.5599 -0.0000 -0.2463 -0.7001 0.0000];
bin = -3:0.5:3;
h = histogram(A, bin);
xticks(bin)
%index of the maximum value
[~,idx] = max(h.Values)
idx = 7
%Range with maximum number of elements
bin(idx:idx+1)
ans = 1×2
0 0.5000
The range can be verified from the histrogram as well.

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