loop to calculate time using previous values
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
Hello everyone!
Could you please help me with a code.
I have a loop and calculated time, so the values of time are the increments between the current and previous values. So how to generate the loop for the time where the previous ones can be added. For example, my first t values are 60.6664, 60.9712, 61.2792, 61.5902, 61.9045........ In the result of new time will be 60.9712, (60.9712+61.2792), (60.9712+61.2792+61.5902)......
W_takeoff = 10000;
W_landing=6000;
S = 20;
AR = 5;
cd0 = 0.02;
k = 1/pi/AR;
RC=0.51;
clalpha = 2*pi;
amin=2;
astall=12;
rho=1;
ct=0.001;
alpha_max=2.95;
cl_max=clalpha*alpha_max*pi/180;
cd_max = cd0 + k * cl_max * cl_max;
delta_w=50;
j=0;
for w=W_takeoff:-delta_w:W_landing
j=j+1;
V(j) = sqrt(2*w/rho/S/cl_max);
D(j) = 0.5 * rho * V(j) * V(j) * S * cd_max;
Thrust(j)=D(j); %for steady level flight condition
F(j)=ct*Thrust(j); %fuel consumption
Weight(j)=w;
t(j)=delta_w/F(j);
R(j)=V(j)*t(j);
end
0 comentarios
Respuestas (1)
Dyuman Joshi
el 31 de Mzo. de 2023
Editada: Dyuman Joshi
el 31 de Mzo. de 2023
You can vectorize the loop -
W_takeoff = 10000;
W_landing = 6000;
S = 20;
AR = 5;
cd0 = 0.02;
k = 1/pi/AR;
RC=0.51;
clalpha = 2*pi;
amin=2;
astall=12;
rho=1;
ct=0.001;
alpha_max=2.95;
cl_max=clalpha*alpha_max*pi/180;
cd_max = cd0 + k * cl_max * cl_max;
delta_w=50;
j=0;
w=W_takeoff:-delta_w:W_landing;
V = (2*w/rho/S/cl_max).^(1/2);
D = 0.5*rho*V.^2*S*cd_max;
Thrust = D;
F = ct*Thrust;
Weight = w;
t = delta_w./F
R = V.*t;
%new time
T = cumsum(t)
2 comentarios
Dyuman Joshi
el 31 de Mzo. de 2023
Editada: Dyuman Joshi
el 4 de Abr. de 2023
Apologies, @Alina Abdikadyr, there was a mistake in the formula of V which has been rectified. Please check my answer again.
Ver también
Categorías
Más información sobre Loops and Conditional Statements en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!