error in arithenco and arithdeco

original=imread('Lena.bmp'); % Read an image Lena 512*512 to original variable

seq=mortonx(original); % convert the matrix original into a vector by morton scan order which is a fucntion i made up by myself

ta=tabulate(seq); % create a three column with the internal function ... first column is the symbol... second is the times it occured ... third is the propability

count=ta(:,2); %copy the count column into count variable from ta variable

code=arithenco(seq,count); %appply the arithmetic coding ...

new=arithdeco(code,count,262144); %apply the arithmetic decoding to restore the original image ...

isequal(seq,new); % to see if seq and new are equal ....

% ??? Error using ==> arithenco at 36
% The symbol sequence parameter must be a vector of positive finite integers.

[vishnu]

can you send the or post the function which converts the image into vector by morton scanning

Answer 1

[Wayne King]

arithenco() expects an input like [1 2 3 4].

what is seq?

[Wayne King]

I mean you told us seq comes from your function mortonx, but is it a vector of positive integers?

Answer 2

[Diyar Aldusky]

mortonx function is a function that just convert the matrix to a vector according to morton scan order .... it dont change the values of the matrix .... it just convert from matrix to vector ... to be from 512*512 to 1*262144 diementions ... and the values mean the same ...you can just type seq=reshape(original,1*262144) ... but after that i get the same error as i get from the begining ...

[Wayne King]

Diyar, it's not important just that it is a vector, what are the values in original, are they all positive integers as I asked you in my first answer.