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Masking images/matrixes

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Amit Ifrach
Amit Ifrach el 14 de Jul. de 2023
Comentada: Image Analyst el 18 de Jul. de 2023
לק"י
Hello!
I got an image of some stained cells:
And I have a grayscale mask such as this:
(different shades are covering different cells as you can see).
I want to systematically go through each gray shade in the mask and to extract (or leave) the area in the cells image.
I looked up for a quick command, but haven't found one.
I tried to use find command, but I get vectors as a result and can't use it to "talk" with the original image matrix.
This is the code I'm using:
img=imread("4.7.23 ut cd4_prfrn acd3+11002c3.tif");
mask=imread("4.7.23 ut cd4_prfrn acd3+11002c3_cp_masks.png");
i=max(max(mask))
maskx=[];
masky=[];
[maskx, masky]=find(mask==i);
imgmasked=img(maskxy,masky)
(I'm using a for loop to go through all indexes, but it will come later, I want to succeed masking right now)
What is the right way to handle this problem please?
Thanks,
Amit.
  2 comentarios
Jon
Jon el 14 de Jul. de 2023
Please attach your two files
Amit Ifrach
Amit Ifrach el 15 de Jul. de 2023
לק"י
Hi jon,
I added them. The cell's picture was converted from TIF to png.
Thanks!

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Respuestas (1)

Image Analyst
Image Analyst el 14 de Jul. de 2023
It looks like your mask is actually a labeled image since each blob seems to have a unique value (label). So in that case to get the area of each labeled blob you'd simply do
props = regionprops(labeledImage, 'Area');
allAreas = [props.Area] % Will give a vector of 5 areas.
  5 comentarios
Matt J
Matt J el 18 de Jul. de 2023
Yes,
imgthldtmp=zeros(size(imgmask));
thldfnd= imgfltrd>(thldmltplr(k)*pxllstavg);
imgthldtmp(thldfnd)=imgfltrd(thldfnd);
Image Analyst
Image Analyst el 18 de Jul. de 2023
Heck no. Shorter would be even more cryptic and hard to follow than it is now. No comments, cryptic variable names, etc. I don't know what you did but whatever, if it works for you, fine.

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