How to do the following nested for loop?

M
M
23 Jul. 2023
2 Respuestas
Respuesta aceptada
Actualizado a las 15 Ag. 2023
5 Visualizaciones (30 días)

0 votos

How to do the following nested for loop?
if there is a vector P = [1 1 1 1 1 1]
and I want to change P in each loop as the following:
first outer loop
inner loop:
first it:
P = [0.1 1 1 1 1 1]
2nd it:
P = [0.2 1 1 1 1 1]
3rd
P = [0.3 1 1 1 1 1]
and so on until reach 0.9
2nd outer loop
P = [1 0.1 1 1 1 1]
2nd it:
P = [1 0.2 1 1 1 1]
3rd
P = [1 0.3 1 1 1 1]
and so on until reach 0.9
3nd outer loop
change the 3rd index as the above.. until reach the 6th outer loop

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 Respuesta aceptada

Voss
Voss el 23 de Jul. de 2023
Ran in:

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Ran in:
format shortg
P = [1 1 1 1 1 1];
P_orig = P;
for ii = 1:numel(P)
fprintf('outer loop iteration %d\n',ii);
P = P_orig;
for jj = 1:9
fprintf('inner loop iteration %d\n',jj);
P(ii) = jj/10;
disp(P)
end
end
outer loop iteration 1
inner loop iteration 1
0.1 1 1 1 1 1
inner loop iteration 2
0.2 1 1 1 1 1
inner loop iteration 3
0.3 1 1 1 1 1
inner loop iteration 4
0.4 1 1 1 1 1
inner loop iteration 5
0.5 1 1 1 1 1
inner loop iteration 6
0.6 1 1 1 1 1
inner loop iteration 7
0.7 1 1 1 1 1
inner loop iteration 8
0.8 1 1 1 1 1
inner loop iteration 9
0.9 1 1 1 1 1
outer loop iteration 2
inner loop iteration 1
1 0.1 1 1 1 1
inner loop iteration 2
1 0.2 1 1 1 1
inner loop iteration 3
1 0.3 1 1 1 1
inner loop iteration 4
1 0.4 1 1 1 1
inner loop iteration 5
1 0.5 1 1 1 1
inner loop iteration 6
1 0.6 1 1 1 1
inner loop iteration 7
1 0.7 1 1 1 1
inner loop iteration 8
1 0.8 1 1 1 1
inner loop iteration 9
1 0.9 1 1 1 1
outer loop iteration 3
inner loop iteration 1
1 1 0.1 1 1 1
inner loop iteration 2
1 1 0.2 1 1 1
inner loop iteration 3
1 1 0.3 1 1 1
inner loop iteration 4
1 1 0.4 1 1 1
inner loop iteration 5
1 1 0.5 1 1 1
inner loop iteration 6
1 1 0.6 1 1 1
inner loop iteration 7
1 1 0.7 1 1 1
inner loop iteration 8
1 1 0.8 1 1 1
inner loop iteration 9
1 1 0.9 1 1 1
outer loop iteration 4
inner loop iteration 1
1 1 1 0.1 1 1
inner loop iteration 2
1 1 1 0.2 1 1
inner loop iteration 3
1 1 1 0.3 1 1
inner loop iteration 4
1 1 1 0.4 1 1
inner loop iteration 5
1 1 1 0.5 1 1
inner loop iteration 6
1 1 1 0.6 1 1
inner loop iteration 7
1 1 1 0.7 1 1
inner loop iteration 8
1 1 1 0.8 1 1
inner loop iteration 9
1 1 1 0.9 1 1
outer loop iteration 5
inner loop iteration 1
1 1 1 1 0.1 1
inner loop iteration 2
1 1 1 1 0.2 1
inner loop iteration 3
1 1 1 1 0.3 1
inner loop iteration 4
1 1 1 1 0.4 1
inner loop iteration 5
1 1 1 1 0.5 1
inner loop iteration 6
1 1 1 1 0.6 1
inner loop iteration 7
1 1 1 1 0.7 1
inner loop iteration 8
1 1 1 1 0.8 1
inner loop iteration 9
1 1 1 1 0.9 1
outer loop iteration 6
inner loop iteration 1
1 1 1 1 1 0.1
inner loop iteration 2
1 1 1 1 1 0.2
inner loop iteration 3
1 1 1 1 1 0.3
inner loop iteration 4
1 1 1 1 1 0.4
inner loop iteration 5
1 1 1 1 1 0.5
inner loop iteration 6
1 1 1 1 1 0.6
inner loop iteration 7
1 1 1 1 1 0.7
inner loop iteration 8
1 1 1 1 1 0.8
inner loop iteration 9
1 1 1 1 1 0.9

Más respuestas (1)

Davide Masiello
Davide Masiello el 23 de Jul. de 2023
Movida: Star Strider el 23 de Jul. de 2023
Ran in:

0 votos

Ran in:
Must you do this with a nested loop?
Example
P0 = [(0.1:0.1:0.9)',ones(9,5)];
P1 = P0;
for i = 1:5
P1 = [P1;circshift(P0,i,2)];
end
disp(P1)
0.1000 1.0000 1.0000 1.0000 1.0000 1.0000 0.2000 1.0000 1.0000 1.0000 1.0000 1.0000 0.3000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 0.5000 1.0000 1.0000 1.0000 1.0000 1.0000 0.6000 1.0000 1.0000 1.0000 1.0000 1.0000 0.7000 1.0000 1.0000 1.0000 1.0000 1.0000 0.8000 1.0000 1.0000 1.0000 1.0000 1.0000 0.9000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.1000 1.0000 1.0000 1.0000 1.0000 1.0000 0.2000 1.0000 1.0000 1.0000 1.0000 1.0000 0.3000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 0.5000 1.0000 1.0000 1.0000 1.0000 1.0000 0.6000 1.0000 1.0000 1.0000 1.0000 1.0000 0.7000 1.0000 1.0000 1.0000 1.0000 1.0000 0.8000 1.0000 1.0000 1.0000 1.0000 1.0000 0.9000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.1000 1.0000 1.0000 1.0000 1.0000 1.0000 0.2000 1.0000 1.0000 1.0000 1.0000 1.0000 0.3000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 0.5000 1.0000 1.0000 1.0000 1.0000 1.0000 0.6000 1.0000 1.0000 1.0000 1.0000 1.0000 0.7000 1.0000 1.0000 1.0000 1.0000 1.0000 0.8000 1.0000 1.0000 1.0000 1.0000 1.0000 0.9000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.1000 1.0000 1.0000 1.0000 1.0000 1.0000 0.2000 1.0000 1.0000 1.0000 1.0000 1.0000 0.3000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 0.5000 1.0000 1.0000 1.0000 1.0000 1.0000 0.6000 1.0000 1.0000 1.0000 1.0000 1.0000 0.7000 1.0000 1.0000 1.0000 1.0000 1.0000 0.8000 1.0000 1.0000 1.0000 1.0000 1.0000 0.9000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.1000 1.0000 1.0000 1.0000 1.0000 1.0000 0.2000 1.0000 1.0000 1.0000 1.0000 1.0000 0.3000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 0.5000 1.0000 1.0000 1.0000 1.0000 1.0000 0.6000 1.0000 1.0000 1.0000 1.0000 1.0000 0.7000 1.0000 1.0000 1.0000 1.0000 1.0000 0.8000 1.0000 1.0000 1.0000 1.0000 1.0000 0.9000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 0.1000 1.0000 1.0000 1.0000 1.0000 1.0000 0.2000 1.0000 1.0000 1.0000 1.0000 1.0000 0.3000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 0.5000 1.0000 1.0000 1.0000 1.0000 1.0000 0.6000 1.0000 1.0000 1.0000 1.0000 1.0000 0.7000 1.0000 1.0000 1.0000 1.0000 1.0000 0.8000 1.0000 1.0000 1.0000 1.0000 1.0000 0.9000
After you produced P1, at each iteration of your code you can just call the next row of the array P1

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Preguntada:

M
M
el 23 de Jul. de 2023

Comentada:

Voss
Voss
el 15 de Ag. de 2023

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