find numbers in a string

Hi,
I have the following example of string 'E_Field (Farfield) (Cartesian) (-0 -1000 -1)(Abs) (cosim Tran1).txt' .
I need to extract the numbers between the brackets 0,1000,-1.
I have tried using the regexp function but without any success.
I will appriciate any kind of assistance.

Respuestas (1)

Chunru
Chunru el 25 de Jul. de 2023
Editada: Chunru el 25 de Jul. de 2023
s = 'E_Field (Farfield) (Cartesian) (-0 -173.648 983.808)(Abs) (cosim Tran1).txt';
s1 = 'E_Field (Farfield) (Cartesian) (-0 -1000 -1)(Abs) (cosim Tran1).txt' ;
p = '(\(-?\d+ -?\d+(.\d*)? -?\d+(.\d*)?\))';
t=regexp(s, p, 'tokens');
t = t{1}{1}
t = '(-0 -173.648 983.808)'
n = sscanf(t, '(%f %f %f)')
n = 3×1
0 -173.6480 983.8080
t1=regexp(s1, p, 'tokens');
t1 = t1{1}{1}
t1 = '(-0 -1000 -1)'
n1 = sscanf(t1, '(%f %f %f)')
n1 = 3×1
0 -1000 -1

5 comentarios

EYAL COHEN
EYAL COHEN el 25 de Jul. de 2023
Chunru Hello,
I thank you for your answer but I would like to add that (1) I need all three numbers inbetween the brackets (2) the string changes. For example, it can be as follows 'E_Field (Farfield) (Cartesian) (-0 -173.648 983.808)(Abs) (cosim Tran1).txt'
Chunru
Chunru el 25 de Jul. de 2023
See the updated.
EYAL COHEN
EYAL COHEN el 25 de Jul. de 2023
It seems to isolate the numbers in the brackets for the second example but fails to the first. The numbers are required to be converted to an array of double.
Chunru
Chunru el 25 de Jul. de 2023
See above
EYAL COHEN
EYAL COHEN el 25 de Jul. de 2023
Movida: Bruno Luong el 25 de Jul. de 2023
It seems to work, I thank you for your help. A big help.

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R2023a

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el 25 de Jul. de 2023

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el 25 de Jul. de 2023

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