how velocize it? (it's possibile to vectorize it?)
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Ntradess =[2 99 1 8 15 67 74 51 58 40
3 80 7 14 16 73 55 57 64 41
3 80 7 20 22 54 56 63 70 47
3 81 7 21 3 60 62 69 71 28
3 81 9 2 9 61 68 75 52 34
4 82 9 83 90 42 49 26 33 65
4 82 9 89 91 48 30 32 39 66
5 85 10 95 97 29 31 38 45 72
6 85 11 96 78 35 37 44 46 53
7 85 12 77 84 36 43 50 27 58
8 86 13 80 84 38 45 51 30 58
8 86 13 82 84 38 45 51 31 58
8 86 13 83 84 38 45 51 31 58
9 87 13 84 84 38 45 51 31 58];
RP_bin=[0 0 1 0 0 1 0 0 1 0 0 1 0 0]';
period=2;
minTrades=2;
g=find(RP_bin>0);
Ntradess_=Ntradess(g,:);
[r,c]=size(Ntradess_);
MinNtrad=zeros(r,c);
for x=1:c %loop colonne
for i=period+1:r
a=Ntradess_(i,x); %n:trade del idx attuale
if a>minTrades
a=find(flip(Ntradess_(1:i-1,x))<=(a-minTrades),1);
if ~isempty(a)
MinNtrad(i,x)= i-a; %MEMORIZZO la posizione della schiera per avere in mintrades richiesti
end
end
end
end
4 comentarios
Dyuman Joshi
el 30 de Jul. de 2023
What is your motivation behind wanting to vectorize the code above?
Walter Roberson
el 30 de Jul. de 2023
You could save some coding effort if you were to use
a = find(Ntradess_(1:i-1,x))<=(a-minTrades), 1, 'last');
if ~isempty(a)
MinNtrad(i,x) = a;
end
The change in logic might make it easier to figure out how to vectorize.
pipin
el 30 de Jul. de 2023
Respuesta aceptada
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