how velocize it? (it's possibile to vectorize it?)

Ntradess =[2 99 1 8 15 67 74 51 58 40
3 80 7 14 16 73 55 57 64 41
3 80 7 20 22 54 56 63 70 47
3 81 7 21 3 60 62 69 71 28
3 81 9 2 9 61 68 75 52 34
4 82 9 83 90 42 49 26 33 65
4 82 9 89 91 48 30 32 39 66
5 85 10 95 97 29 31 38 45 72
6 85 11 96 78 35 37 44 46 53
7 85 12 77 84 36 43 50 27 58
8 86 13 80 84 38 45 51 30 58
8 86 13 82 84 38 45 51 31 58
8 86 13 83 84 38 45 51 31 58
9 87 13 84 84 38 45 51 31 58];
RP_bin=[0 0 1 0 0 1 0 0 1 0 0 1 0 0]';
period=2;
minTrades=2;
g=find(RP_bin>0);
Ntradess_=Ntradess(g,:);
[r,c]=size(Ntradess_);
MinNtrad=zeros(r,c);
for x=1:c %loop colonne
for i=period+1:r
a=Ntradess_(i,x); %n:trade del idx attuale
if a>minTrades
a=find(flip(Ntradess_(1:i-1,x))<=(a-minTrades),1);
if ~isempty(a)
MinNtrad(i,x)= i-a; %MEMORIZZO la posizione della schiera per avere in mintrades richiesti
end
end
end
end

4 comentarios

Dyuman Joshi
Dyuman Joshi el 30 de Jul. de 2023
What is your motivation behind wanting to vectorize the code above?
pipin
pipin el 30 de Jul. de 2023
Editada: pipin el 30 de Jul. de 2023
I think that encoded like this is slow
I use "find.". maybe it's not very efficient and it can be avoided (I ask)
You could save some coding effort if you were to use
a = find(Ntradess_(1:i-1,x))<=(a-minTrades), 1, 'last');
if ~isempty(a)
MinNtrad(i,x) = a;
end
The change in logic might make it easier to figure out how to vectorize.
pipin
pipin el 30 de Jul. de 2023
thank

Iniciar sesión para comentar.

 Respuesta aceptada

Bruno Luong
Bruno Luong el 30 de Jul. de 2023
Editada: Bruno Luong el 31 de Jul. de 2023
I don't know the memory requirement would go up if I vectorize the outer loop in a non-toy case. So I leave it for now.
Ntradess =[2 99 1 8 15 67 74 51 58 40
3 80 7 14 16 73 55 57 64 41
3 80 7 20 22 54 56 63 70 47
3 81 7 21 3 60 62 69 71 28
3 81 9 2 9 61 68 75 52 34
4 82 9 83 90 42 49 26 33 65
4 82 9 89 91 48 30 32 39 66
5 85 10 95 97 29 31 38 45 72
6 85 11 96 78 35 37 44 46 53
7 85 12 77 84 36 43 50 27 58
8 86 13 80 84 38 45 51 30 58
8 86 13 82 84 38 45 51 31 58
8 86 13 83 84 38 45 51 31 58
9 87 13 84 84 38 45 51 31 58];
RP_bin=[0 0 1 0 0 1 0 0 1 0 0 1 0 0]';
period=2;
minTrades=2;
g=find(RP_bin>0);
Ntradess_=Ntradess(g,:);
[r,c]=size(Ntradess_);
MinNtrad=zeros(r,c);
for x=1:c %loop colonne
for i=period+1:r
a=Ntradess_(i,x); %n:trade del idx attuale
if a>minTrades
a=find(flip(Ntradess_(1:i-1,x))<=(a-minTrades),1);
if ~isempty(a)
MinNtrad(i,x)= i-a; %MEMORIZZO la posizione della schiera per avere in mintrades richiesti
end
end
end
end
MinNtrad
MinNtrad = 4×10
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 2 2 2 2 1 0 0 2 2 1 3 2 3 1 3 3 3 3 0 3
[r,c]=size(Ntradess_);
MinNtrad = zeros(r,c);
Mask = flip(triu(true(r),1),1);
for x = 1:c
nx = Ntradess_(:,x);
[v,j] = max(Mask .* (nx'-flip(nx,1) >= minTrades), [], 1);
j = r+1-j;
j(v(:)==0 | nx(:)<=minTrades) = 0;
MinNtrad(:,x) = j;
end
MinNtrad(1:period,:) = 0;
MinNtrad
MinNtrad = 4×10
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 2 2 2 2 1 0 0 2 2 1 3 2 3 1 3 3 3 3 0 3

2 comentarios

Bruno Luong
Bruno Luong el 30 de Jul. de 2023
Editada: Bruno Luong el 31 de Jul. de 2023
Full vectorize
warning: potential runout of memory
[r,c] = size(Ntradess_);
Mask = (1:r)' > (r:-1:1); % flip(triu(true(r),1),1);
D = reshape(Ntradess_, [1 r c]) - reshape(flip(Ntradess_, 1), [r 1 c]);
B = Mask .* (D >= minTrades);
[V,J] = max(B, [], 1);
MinNtrad = r+1-reshape(J, [r c]);
V = reshape(V, [r c]);
MinNtrad(V==0 | Ntradess_<=minTrades) = 0;
MinNtrad(1:period,:) = 0;
pipin
pipin el 31 de Jul. de 2023
Editada: pipin el 31 de Jul. de 2023
congrats for the vectorization....but i don't use it it requires a lot of free memory

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre Simulink en Centro de ayuda y File Exchange.

Etiquetas

Preguntada:

el 30 de Jul. de 2023

Editada:

el 31 de Jul. de 2023

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by