Why doesn't timezone work with datetime

I want to convert a posix time to a datetime for the time zone at a specific longitude. The timezone function gives you the time zone at a specific longitude, but none of the outputs are accepted by datetime.
[a,b,c] = timezone(-80)
a = 5
b = 'R'
c = '+5 R'
try
datetime(1685585049.879,'ConvertFrom','posixtime','TimeZone',a)
end
try
datetime(1685585049.879,'ConvertFrom','posixtime','TimeZone',b)
end
try
datetime(1685585049.879,'ConvertFrom','posixtime','TimeZone',c)
end

 Respuesta aceptada

The timezone function is from the Mapping Toolbox, and its results are not compatible with the datetime function. The otherwise compatible timezones function does not take longitude arguments.
Try this instead —
TZ = string(fix(-80/15)) % Time Zone (-80° Longitude)
TZ = "-5"
Time = datetime(1685585049.879,'ConvertFrom','posixtime','TimeZone',TZ)
Time = datetime
31-May-2023 21:04:09
.

Más respuestas (1)

Seth Furman
Seth Furman el 14 de Sept. de 2023
Editada: Seth Furman el 14 de Sept. de 2023
Adding to @Star Strider's answer:
The value of TimeZone can be an ISO 8601 character vector of the form +HH:mm or -HH:mm; for example, '+01:00', to specify a time zone that is a fixed offset from UTC.
lon = 80;
zd = timezone(lon)
zd = -5
tz = compose("%+03d:00",zd)
tz = "-05:00"
dt = datetime(1685585049.879,ConvertFrom="posixtime",TimeZone=tz)
dt = datetime
31-May-2023 21:04:09

Categorías

Productos

Versión

R2023a

Preguntada:

AB
el 24 de Ag. de 2023

Editada:

el 14 de Sept. de 2023

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by