ploting Mitagg leffler function

2 visualizaciones (últimos 30 días)
Erm
Erm el 10 de Sept. de 2023
Respondida: Sulaymon Eshkabilov el 10 de Sept. de 2023
Hello h
How can I plote the Mittage leffler for the function in [0,50], Here is the code but I do not know how to define the function.
I appreciate your help.
alpha=0.5;
beta=1.2;
function E= ML(z,alpha,beta)
plot(E)
end

Respuestas (3)

Sulaymon Eshkabilov
Sulaymon Eshkabilov el 10 de Sept. de 2023
Follow this approach. Let's say you'd need to plot: f(a, b, t) = a*exp(cos(b*t)) using a nested function.
a = 2.13;
b = 3.5;
t = linspace(-10, 10, 500);
OUTPUT=My_Fun(a, b, t);
function F = My_Fun(a, b, t)
F = a*exp(cos(b*t));
plot(t, F)
end
  5 comentarios
Erm
Erm el 10 de Sept. de 2023
E is sum_{k=0}^{infty} z^k/Gamma(alpha*k+beta) and I wrote it as
syms k z alpha beta
E=symsum(z^k/gamma(alpha*k+beta),k,0,Inf)
but still not working
Walter Roberson
Walter Roberson el 10 de Sept. de 2023
alpha = sym(0.5);
beta = sym(1.2);
syms k z
E(z) = symsum(z^k/gamma(alpha*k+beta),k,0,Inf)
E(z) = 
t = linspace(-10, 10, 50).';
Y = E(sqrt(sym(t)))
Y = 
y = double(Y);
subplot(2,1,1); plot(t, real(y), 'k-.'); title('real part');
subplot(2,1,2); plot(t, imag(y), 'r:.'); title('imag part')

Iniciar sesión para comentar.


Walter Roberson
Walter Roberson el 10 de Sept. de 2023

Sulaymon Eshkabilov
Sulaymon Eshkabilov el 10 de Sept. de 2023
As shown in one of the matlab exchange, edit this below shown function file using your own input variables, viz. k, z, alpha, beta
a = ?;
b = ?;
c = ?;
x = ?;
OUTPUT=ML_fun(a, b, c, x);
function f=ML_fun(a,b,c,x)
gamma_c=1.0/gamma(c);
f=0; fa=1; j=0;
while norm(fa,1)>=eps
fa=(gamma(c+j)*gamma_c)/gamma(j+1)/gamma(a*j+b) *x.^j;
f=f+fa; j=j+1;
% You can also add: plot(), hold on % see the simulation progress of ML
% fcn
end
% Or here: plot()
end

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