How to plot locations on a polar stereographic map?

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Ashfaq Ahmed
Ashfaq Ahmed el 18 de Sept. de 2023
Comentada: Ashfaq Ahmed el 18 de Sept. de 2023
Hi all!
I have a list of Latitude coordinates,
LAT = [85.6494200000000 85.6510100000000 85.6525200000000 85.6539900000000 85.6554000000000 85.6567700000000
85.6581100000000 85.6593800000000 85.6606300000000 85.6618700000000 85.6631100000000 85.6643700000000 85.6656700000000
85.6670100000000 85.6683600000000 85.6698100000000 85.6713200000000 85.6729100000000 85.6745400000000 85.6762300000000
85.6779200000000 85.6795900000000 85.6812600000000 85.6828700000000 85.6844300000000 85.6859100000000 85.6873100000000
85.6886400000000 85.6899100000000 85.6911500000000];
and a list of longitude coordinates,
LON = [125.496810000000 125.477850000000 125.459710000000 125.442220000000 125.425140000000 125.408300000000
125.391110000000 125.373610000000 125.354860000000 125.334610000000 125.313290000000 125.291040000000 125.267750000000
125.243540000000 125.218690000000 125.193170000000 125.166710000000 125.139900000000 125.113540000000 125.087610000000
125.062750000000 125.039550000000 125.017760000000 124.997280000000 124.978000000000 124.959800000000 124.942560000000
124.926030000000 124.910060000000 124.894060000000];
Can anyone help me writing a code that plots the moving locations of the tracer in a polar stereographic map?
  3 comentarios
Dyuman Joshi
Dyuman Joshi el 18 de Sept. de 2023
The distances between the points you have are extremely small compared to the surface area of the earth -
LAT = [85.6494200000000 85.6510100000000 85.6525200000000 85.6539900000000 85.6554000000000 85.6567700000000 ...
85.6581100000000 85.6593800000000 85.6606300000000 85.6618700000000 85.6631100000000 85.6643700000000 85.6656700000000 ...
85.6670100000000 85.6683600000000 85.6698100000000 85.6713200000000 85.6729100000000 85.6745400000000 85.6762300000000 ...
85.6779200000000 85.6795900000000 85.6812600000000 85.6828700000000 85.6844300000000 85.6859100000000 85.6873100000000 ...
85.6886400000000 85.6899100000000 85.6911500000000];
LON = [125.496810000000 125.477850000000 125.459710000000 125.442220000000 125.425140000000 125.408300000000 ...
125.391110000000 125.373610000000 125.354860000000 125.334610000000 125.313290000000 125.291040000000 125.267750000000 ...
125.243540000000 125.218690000000 125.193170000000 125.166710000000 125.139900000000 125.113540000000 125.087610000000 ...
125.062750000000 125.039550000000 125.017760000000 124.997280000000 124.978000000000 124.959800000000 124.942560000000 ...
124.926030000000 124.910060000000 124.894060000000];
%Setting Lat Limits based on the data
axesm('stereo','MapLatLimit',[75 90])
load coastlines
plotm(coastlat,coastlon)
%Setting higher line width to display the points
plotm(LAT,LON,'r-','LineWidth',20)
Ashfaq Ahmed
Ashfaq Ahmed el 18 de Sept. de 2023
Thank you!!

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Respuesta aceptada

Chad Greene
Chad Greene el 18 de Sept. de 2023
With Antarctic Mapping Tools, use plotps. Use plotpsn in the Arctic Mapping toolbox for northern hemisphere.

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