Number of filter taps in Gaussian filter design

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Jay
Jay el 24 de Sept. de 2023
Comentada: Jay el 24 de Sept. de 2023
Hello,
I'm desinging a pulse shaping filter where the filter covers a span of 5 inputs symbols and 12 times of input symbol rate (e.g., 3.25 MHz). So I tried to use "gaussdesign" with parameter BT = 0.3, span = 5, and sps = 12.
I was expecting 60 coefficients which can be implemented with a polyphase FIR filter with a total 12 phases. However, the design with "gaussdesign" generated 61 taps. So what's happening here...? Am I missing something?
Thanks,
Jay

Respuesta aceptada

Paul
Paul el 24 de Sept. de 2023
Hi Jay,
"The number of symbols between the start and end of the impulse (span) and the number of samples per symbol (sps) determine the length of the impulse response: span×sps+1."
The impulse response for the given parameters is of length 61 and the number of delays needed to realize such a filter is 60, i.e.,
H(z) = h[0] + h[1]*z^-1 + .... h[60]*z^-60.
So there are 60 "taps," if by tap we mean "delay element."
  3 comentarios
Paul
Paul el 24 de Sept. de 2023
I don't why span x sps must be even.
My guess is that it's important to have the impulse response be symmetric around the peak, which can only occur if the duration of the impulse response, span*sps + 1, is odd.
Jay
Jay el 24 de Sept. de 2023
One realization might be simpler than the other but both filters are implementable for sure whatever even or odd number of taps. Putting this restriction in MATLAB sounds strange to me.
Thanks Paul for the discussion. It helps.

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