Read data with repeat counts
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Geetartha Dutta
el 6 de Oct. de 2023
Respondida: Voss
el 6 de Oct. de 2023
I have a data file containing numbers with repeat counts denoted by asterisk of the following format: 750.013 2*748.943 2*748.221 ... which is equivalent to 750.013 748.943 748.943 748.221 748.221 ... How can I read this data into a vector? That is, how can I take into account the repeat count operator (*) while reading the data?
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Voss
el 6 de Oct. de 2023
str = fileread('file.txt')
C = regexp(regexp(str,'\s+','split'),'\*','split');
idx = cellfun(@isscalar,C);
C(idx) = cellfun(@(x)[{'1'} x],C(idx),'UniformOutput',false);
M = str2double(vertcat(C{:}));
V = repelem(M(:,2).',M(:,1))
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Más respuestas (2)
Mathieu NOE
el 6 de Oct. de 2023
hello
maybe this ?
data_string = "750.013 2*748.943 2*748.221"; % data imported as string array
data_string2 = split(data_string,' ');
%% main loop
store_value = [];
for k = 1:numel(data_string2)
tmp = char(data_string2(k));
ind = strfind(tmp,"*");
if ~isempty(ind) % we have 2*748.943 data (or alike
factor = str2num(tmp(1:ind-1));
value = str2num(tmp(ind+1:end));
value_all = repmat(value,[factor 1]);
store_value = [store_value;value_all];
else % we have a single value
store_value = [store_value;str2num(tmp)];
end
end
store_value
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Dyuman Joshi
el 6 de Oct. de 2023
@Mathieu NOE, rather than growing the output dynamically, a better approach would be to preallocate according to the size of data_string2, find and store the number before asterisk for each element (if it does not exist, assign 1) and then use repelem on the unique elements.
Les Beckham
el 6 de Oct. de 2023
Here is one approach.
data_strings = ["750.013"; "2*748.943"; "2*748.221"] % sample input data
iData = 1;
for iStr = 1:numel(data_strings)
if contains(data_strings(iStr), "*")
tmp = split(data_strings(iStr), "*");
rpt = str2double(tmp(1));
data(iData:(iData + rpt - 1)) = str2double(tmp(2));
else
rpt = 1;
data(iData) = str2double(data_strings(iStr));
end
iData = iData + rpt;
end
disp(data)
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