if difference between two values is smaller than replace by
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Kai
el 22 de Oct. de 2023
Comentada: Dyuman Joshi
el 23 de Oct. de 2023
I have a vector that contains several time values. For the application I need to check if the difference between two values is smaller than 3e-6. If that's the case the second (higher) value shall be replaced with the first.
My approach would be for-loops but maybe there is a smarter and more efficient way to solve this?
5 comentarios
the cyclist
el 22 de Oct. de 2023
Is each column processed independently?
It doesn't seem that any value is greater than the immediately preceding value by less than 3.e-6, but more than zero:
load("time.mat","time")
any((diff(time) > 0) & (diff(time) < 3.e-6),"all")
Walter Roberson
el 22 de Oct. de 2023
Editada: Walter Roberson
el 22 de Oct. de 2023
load("time.mat","time")
dt = diff(time);
dt = dt(dt ~= 0);
min(dt)
So in all cases where the difference in times is < 3e-6, the two values are already identical.
Respuesta aceptada
Pratyush
el 23 de Oct. de 2023
Hi Kai,
I understand that you have a vector, and if the difference between any two values is less than 3e-6, you want to set them both equal to the lesser of the two numbers. The following script could be used for that purpose:
% Sort timeValues vector
timeValues = sort(timeValues);
% Calculate the differences between adjacent values
diffValues = diff(timeValues);
% Find the indices where the differences are smaller than 3e-6
replaceIndices = find(diffValues < 3e-6);
% Replace the second value with the first for the identified indices
timeValues(replaceIndices + 1) = timeValues(replaceIndices);
Hope this helps.
1 comentario
Dyuman Joshi
el 23 de Oct. de 2023
Note that this answer sorts the data before finding difference between consecutive elements.
OP has/had not specified anything in regards to that.
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