problem with numerical derivative using gradient function

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Kobi
Kobi el 15 de Abr. de 2015
Comentada: Michael Mauersberger el 30 de Abr. de 2020
while using gradient i encounter a phenomenon that i cannot explain, as you can see from the example below
a=[1 2 7 9;
9 8 4 1;
1 2 3 7]
gradient(a)
ans =
1.0000 3.0000 3.5000 2.0000
-1.0000 -2.5000 -3.5000 -3.0000
1.0000 1.0000 2.5000 4.0000
i get this weird 3.5 value that is not expected all i need's a simple derivative that subtract one value with another similar to the diff function where i get this result
a=[1 2 7 9;
9 8 4 1;
1 2 3 7]
diff(a)
ans =
8 6 -3 -8
-8 -6 -1 6
the problem with diff is that i don't get the same matrix size

Respuestas (1)

Star Strider
Star Strider el 15 de Abr. de 2015
You’re only getting half the information that gradient is calculating.
Use this to get the gradient in the default (horizontal, along rows) direction as well as the vertical (along columns) direction:
[dadx,dady] = gradient(a)
The diff function takes the difference in the first dimension >1 by default. (You can specify a different dimension as the third argument.) So if a matrix, it will take the differences between rows (along columns) by default.
So if you want the output of gradient to correspond with the default output of diff, use the second output of gradient, here ‘dady’ in my code.
  3 comentarios
Star Strider
Star Strider el 15 de Abr. de 2015
No, there is nothing suspicious about the gradient function. (See the documentation — doc gradient — for the algorithm it uses.) It produces an accurate numerical derivative, not simply the difference between adjacent elements as diff does. If there is a specific, constant, spacing between the elements in each direction that you want to provide, gradient will use them rather than the default spacing of 1.
Michael Mauersberger
Michael Mauersberger el 30 de Abr. de 2020
I agree. Furthermore gradient calculates mean values of neighbouring differences. That is why you get a .5 value. All is written in the doc.

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