Using repelem to vertially concatonate non-numeric variable

4 visualizaciones (últimos 30 días)
Emu
Emu el 9 de Nov. de 2023
Movida: Stephen23 el 23 de Sept. de 2024
I have a variable in format 1001_1_1 that changes in a loop. I want to replicate and vertcat this by different amounts each loop, to a new variable eg
1001_1_1
1001_1_1
3005_3_5
3005_3_5
3005_3_5
and so on.
Ive tried using repelem:
new_var = repelem(name, n)
new_var_all = [new_var_all; new_var];
but if e.g. n=3, this is the result: 111000000666___111___333
Please help!

Respuesta aceptada

Star Strider
Star Strider el 9 de Nov. de 2023
I am not certain what you want to do, however the repmat function might be a better choice, since it allows the dimensions to be specified.
v = '1001_1_1';
new_var = repmat(v, 3, 1)
new_var = 3×8 char array
'1001_1_1' '1001_1_1' '1001_1_1'
.
  1 comentario
Atsushi Ueno
Atsushi Ueno el 9 de Nov. de 2023
n = 3;
new_var_all = [];
name = {'1001_1_1';'3005_3_5';'6007_7_9'};
for k = 1:size(name)
new_var = repmat(name{k}, n, 1);
new_var_all = [new_var_all; new_var];
end
new_var_all
new_var_all = 9×8 char array
'1001_1_1' '1001_1_1' '1001_1_1' '3005_3_5' '3005_3_5' '3005_3_5' '6007_7_9' '6007_7_9' '6007_7_9'

Iniciar sesión para comentar.

Más respuestas (2)

Stephen23
Stephen23 el 9 de Nov. de 2023
Editada: Stephen23 el 9 de Nov. de 2023
".. repmat function might be a better choice, since it allows the dimensions to be specified."
As does REPELEM:
repelem('1001_1_1',3,1)
ans = 3×8 char array
'1001_1_1' '1001_1_1' '1001_1_1'

Steven Lord
Steven Lord el 9 de Nov. de 2023
Note that the for loop approach from @Atsushi Ueno works if the "pieces" of the names are the same length all the way down the list. But if you had:
name = {'1001_1_1';'3005_3_5';'6007_7_10'}; % 10 not 9
you'd receive an error. In this case, I'd use a string array and repmat or repelem as @Star Strider and @Stephen23 suggested.
names = ["1001_1_1";"3005_3_5";"6007_7_10"];
R = repelem(names, 3, 1)
R = 9×1 string array
"1001_1_1" "1001_1_1" "1001_1_1" "3005_3_5" "3005_3_5" "3005_3_5" "6007_7_10" "6007_7_10" "6007_7_10"
If you need the elements as char vectors (because a function you're trying to use only supports char vectors or would need to be modified to support string arrays, like if it uses concatenation to combine the name with something else) you can call char.
c = char(R(8))
c = '6007_7_10'
Another possibility, if you're trying to assemble these names from all combinations of the "pieces", is to use combinations and join.
C = combinations([1001, 3005, 6007], [1, 3, 7], [1, 5, 10]);
join(string(C.Variables), "_")
ans = 27×1 string array
"1001_1_1" "1001_1_5" "1001_1_10" "1001_3_1" "1001_3_5" "1001_3_10" "1001_7_1" "1001_7_5" "1001_7_10" "3005_1_1" "3005_1_5" "3005_1_10" "3005_3_1" "3005_3_5" "3005_3_10" "3005_7_1" "3005_7_5" "3005_7_10" "6007_1_1" "6007_1_5" "6007_1_10" "6007_3_1" "6007_3_5" "6007_3_10" "6007_7_1" "6007_7_5" "6007_7_10"

Categorías

Más información sobre Matrices and Arrays en Help Center y File Exchange.

Productos


Versión

R2023b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by