Hello, the question is, is it possible to set an interval in y when plotting a graph, if the interval is already set in x?

3 comentarios

Dyuman Joshi
Dyuman Joshi el 22 de Nov. de 2023
It's not clear to me what you want to do.
Could you elaborate on this and provide more information? An example alongside would be helpful.
Maria
Maria el 22 de Nov. de 2023
I have a task to build a graph of a trigonometric equation (cos(2*t))^(-2) - (sin(2*t))^(-2) =8/3), I build the graph as follows (I will attach part of the program) , but they told me that I need to limit the schedule by f, but I didn’t find information about this
t = 0:0.01:3*pi;
f= (cos(2*t)).^(-2) - (sin(2*t)).^(-2) - 8/3;
figure;
plot(t, f, 'LineWidth', 2);
xlabel('t');
ylabel('y');
title('График уравнения');
grid on;
Dyuman Joshi
Dyuman Joshi el 22 de Nov. de 2023
"but they told me that I need to limit the schedule by f"
I do not understand this. Can you explain a bit more about this?
Also, do you know what is the expected output? If yes, then please share.

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 Respuesta aceptada

Sam Chak
Sam Chak el 22 de Nov. de 2023
The ylim() command can be used to set the interval on the y-axis.
x = -1:0.01:1;
y = x.^3 - 0.25*x.^2 - 0.5*x;
figure (1)
plot(x, y), grid on
figure (2)
plot(x, y), grid on, ylim([-0.4, 0.2])

2 comentarios

Maria
Maria el 22 de Nov. de 2023
Thank you it works @Sam Chak
You are welcome, @Maria. If you find the solution helpful, please consider clicking 'Accept' ✔ on the answer and voting 👍 for it.
By the way, the function has singularities (division-by-zero events). That's why the plot shows the discontinuities.
t = 0:0.01:3*pi;
f = (cos(2*t)).^(-2) - (sin(2*t)).^(-2) - 8/3;
figure;
plot(t, f, 'LineWidth', 2);
ylim([-20 20])
xlabel('t');
ylabel('y');
title('График уравнения');
grid on;

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