solve function answer is a 2x1 matrix . how to assign it directly to 2 variables ?

v=[2;0;2;1;0;9;3;9;6];
m=max(v);
n=mean(v);
syms x
f=@(x) 2*n-x;
g=@(x) (n/6)*x.^2-2*m;
ezplot(f,[-10,10]);
hold on
ezplot(g,[-10,10]);
grid on
title ('graphs of f(𝑥) and g(𝑥)')
legend ('f(x)','g(x)');

s=round(solve( 2*n-x == (n/6)*x.^2-2*m ,x),5);
'x1=manually input (1st ans given by solve function above)';
'x2=manually input (2nd ans given by solve function above)';
a=int(2*n-x-(n/6)*x.^2+2*m,x1,x2);

Unrecognized function or variable 'x1'.

[Ruqaya]

i need s answer to show the following : x1= "first ans" & x2= ""2nd ans""

[Dyuman Joshi]

Note - The use of ezplot is not recommend. Use fplot instead.

Also, look into disp and fprintf / sprintf

Answer 1

[John D'Errico]

For example, I'll compute the mean of an array, which here will generate a vector of length 2.

A = rand(10,2);
mean(A,1)

ans = 1×2

0.4834 0.4685

Define this function handle:

splitvec = @(x) deal(x(1),x(2));

Now I can use that little toy I just built.

[xm1,xm2] = splitvec(mean(A,1))

xm1 = 0.4834

xm2 = 0.4685

It directly takes a vector of length 2, and returns 2 distinct variables. Personally, I will tell you that is a bad idea. That it is better to just return a vector, and index into it.

Of course, this works as well on symbolic results.

syms y
[y1,y2] = splitvec(solve(y^2 - 1 == 0,y))

y1 = 

y2 = 

1

[Ruqaya]

thanks that was helpful :)