I code a bisection method on MATLAB app designer, how can I fix this error ?

14 visualizaciones (últimos 30 días)
typefunction = app.TypefunctionEditField.Value;
a = app.aEditField.Value
b = app.bEditField.Value
run = app.RunButton.ButtonPushedFcn
error= app.errorEditField.Value
fxi=str2func(['@(x)'typefunction]);
number_of_iterations=0;
if fxi(a)*fxi(b)>0
result=NaN;
return
end
if fxi(a)==0
result=a;
return
elseif fxi(b)==0
result=b;
return
end
while(abs(a-b)>=error)
result=(a+b)/2;
if fxi(a)*fxi(result)<0
b=result;
else
a=result;
end
number_of_iterations=number_of_iterations+1;
end

Respuestas (1)

Walter Roberson
Walter Roberson el 30 de Nov. de 2023
fxi=str2func(['@(x)'typefunction]);
You need a space or comma, like
fxi=str2func(['@(x)' typefunction]);
  2 comentarios
Anne
Anne el 30 de Nov. de 2023
i fix it but it still have same error :(
Walter Roberson
Walter Roberson el 30 de Nov. de 2023
I copied your posted code into the editor, and added in the one space that I indicate, and that cleared up the error message. There are still warnings recommending that you add in semi-colons to prevent unnecessary output, but the error is gone just by putting in that one space.

Iniciar sesión para comentar.

Categorías

Más información sobre Environment and Settings en Help Center y File Exchange.

Etiquetas

Productos


Versión

R2018b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by