Error using plot for Fourier series

4 visualizaciones (últimos 30 días)
Tashanda Rayne
Tashanda Rayne el 17 de Dic. de 2023
Editada: Torsten el 18 de Dic. de 2023
This is not plotting. I tried applying fplot and plot and neither will work. I have assigned t so im not sure why I keep getting the error:
"Error using plot
Data must be numeric, datetime, duration or an array convertible to double.
Error in Fourier_example_3 (line 48)
plot(x,F3, 'b' )"
This is my code:
% Fourier Series
clear all
syms x k L t
c = 1
f1(x) = x;
f2(x) = L-x;
f1 = simplify(f1);
f2 = simplify(f2);
%Solving for Bn
b(k) = (2/L)*int(f1*sin(k*pi*x/L),[0,L/2]);
b1(k) = (2/L)*int(f2*sin(k*pi*x/L),[L/2,L]);
Bn(k) = b1 + b;
Bn = simplify(Bn);
N=100;
x = linspace(-L+0.000001,L,N);
t = [0 50 100 200];
for i = 1:1:N
F = Bn.*sin(pi.*x./L).*exp((-(c.*(pi.^2))/L.^2).*0);
end
for i = 1:1:N
F1 = Bn.*sin(pi.*x./L).*exp((-(c.*(pi.^2))/L.^2).*50);
end
for i = 1:1:N
F2 = Bn.*sin(pi.*x./L).*exp((-(c.*(pi.^2))/L.^2).*100);
end
for i = 1:1:N
F3 = Bn.*sin(pi.*x./L).*exp((-(c.*(pi.^2))/L.^2).*200);
end
plot(x,F3, 'b' )
plot(x,F,'--r')
plot(x,F1,'--p')
plot(x,F2,'-r')
xlabel('x')
ylabel('y')
legend('f','F(x) N=10', 'F(x) N=100','F(x) N=500','location','best')
grid on
hold off

Respuestas (2)

Star Strider
Star Strider el 17 de Dic. de 2023
The fplot function is usually best for symbolic functions.
I am not certain what you want to plot.
Try this —
syms x k L t
c = 1;
L = 80;
f1(x) = x;
f2(x) = L-x;
f1 = simplify(f1);
f2 = simplify(f2);
%Solving for Bn
b(k) = (2/L)*int(f1*sin(k*pi*x/L),[0,L/2]);
b1(k) = (2/L)*int(f2*sin(k*pi*x/L),[L/2,L]);
Bn(k) = b1 + b;
Bn = simplify(Bn)
Bn(k) = 
figure
fplot(Bn,[-L L])
grid
xlabel('k')
ylabel('Bn(k)')
.
  4 comentarios
Tashanda Rayne
Tashanda Rayne el 18 de Dic. de 2023
I am attempting to have this code run for different t and k values. I took k out when the code wasnt working. It now looks like this, my apologies. I don't know how to get the code to run
tried fplot and it still is giving me an error :
syms x k L t
c = 1;
f1(x) = x;
f2(x) = L-x;
f1_simplified = simplify(f1);
f2_simplified = simplify(f2);
%Solving for Bn
b(x) = (2/L)*int(f1_simplified*sin(k*pi*x/L),[0,L/2]);
b1(x) = (2/L)*int(f2_simplified*sin(k*pi*x/L),[L/2,L]);
Bn(x) = b1 + b;
Bn_simplified = simplify(Bn);
N = 100;
x = linspace(-pi,pi,N);
t = [0;0.1;0.5;2];
k = 5
for i = 1:2:k
F = Bn_simplified.*sin(k*pi.*x./L).*exp((-(c.*(pi.^2))/L.^2).*t);
end
hold on
fplot(F , [-L,L])
Walter Roberson
Walter Roberson el 18 de Dic. de 2023
x = linspace(-pi,pi,N);
That is a vector.
for i = 1:N
F = Bn_simplified.*sin(pi.*x./L).*exp((-(c.*(pi.^2))/L.^2).*0);
end
The right hand side involves the vector F, so the left hand side will be a vector.
Each iteration you overwrite all of F, so the result is going to be the last value assigned to it... which is the same as the first value assigned to it.
fplot(F , [-L,L])
F is a vector of symbolic values, so you are asking to fplot() a symbolic vector. That isn't going to work very well.

Iniciar sesión para comentar.


Torsten
Torsten el 18 de Dic. de 2023
Editada: Torsten el 18 de Dic. de 2023
I'm not sure what you try to do. Maybe something like this:
clear all
syms x
L = 2;
f = piecewise(x<=L/2,x,x>L/2,(L-x));
N = 5;
b = 2/L*int(f*sin((1:N)*pi*x/L),x,[0,L]);
F{1} = 0;
for k = 1:N
F{k+1} = F{k} + b(k)*sin(pi*k*x/L);
end
hold on
fplot(F,[0 L])
fplot(f,[0 L])
hold off
grid on
  2 comentarios
Tashanda Rayne
Tashanda Rayne el 18 de Dic. de 2023
This worked but I need to specify the t. The complete equation for
F = Bn_simplified.*sin(k*pi.*x./L).*exp((-(c.*(pi.^2))/L.^2).*t);
Torsten
Torsten el 18 de Dic. de 2023
Editada: Torsten el 18 de Dic. de 2023
Why not simply multiplying F by the factor ?
syms x
t = 1;
c = 1;
L = 2;
f = piecewise(x<=L/2,x,x>L/2,(L-x));
N = 5;
b = 2/L*int(f*sin((1:N)*pi*x/L),x,[0,L]);
F{1} = 0;
for k = 1:N
F{k+1} = F{k} + b(k)*sin(pi*k*x/L)*exp(-c*pi^2/L^2*t);
end
hold on
fplot(F,[0 L])
fplot(f,[0 L])
hold off
grid on

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