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Why do I get "Array indices must be positive integers or logical values" when I am trying to plot my functions?

1 visualización (últimos 30 días)
figure(1)
alpha=0.89;
beta=0.89;
gamma=0.5;
c(0)=1;
i(0)=1;
y(0)=2;
for t=1:50
y(t) = c(t) + i(t);
c(t) = alpha*y(t - 1);
i(t) = beta*(c(t) - c(t - 1)) + gamma;
end
plot(y,'LineWidth',2)
hold on
plot(c,'LineWidth',2)
plot(i,'LineWidth',2)
xlabel('Time period')
ylabel('BKT (M€)')
Hey! I am trying to plot this, but for some reason I get the message "Array indices must be positive integers or logical values". What seems to be the problem in my code?

Respuesta aceptada

Mathieu NOE
Mathieu NOE el 31 de En. de 2024
hello
1/ matlab is a language where indexing is 1 based and not zero based
2/ next correction is that y must be computed once c and i are updated in the for loop
so a working code is :
figure(1)
alpha=0.89;
beta=0.89;
gamma=0.5;
c(1)=1;
i(1)=1;
y(1)=2;
for t=2:50
c(t) = alpha*y(t - 1);
i(t) = beta*(c(t) - c(t - 1)) + gamma;
y(t) = c(t) + i(t);
end
plot(y,'LineWidth',2)
hold on
plot(c,'LineWidth',2)
plot(i,'LineWidth',2)
xlabel('Time period')
ylabel('BKT (M€)')

Más respuestas (2)

Austin M. Weber
Austin M. Weber el 31 de En. de 2024
Editada: Austin M. Weber el 31 de En. de 2024
In MATLAB, indexing starts at 1, so you cannot have C(0), i(0), or y(0). Rather, it needs to be C(1), i(1), or y(1).
EDIT: @Mathieu NOE is correct, in addition to what I said, that also means that you need to start your for-loop at index position 2 instead of position 1. Otherwise, when your script gets to this line:
for t = 1:50
c(t) = alpha*y(t - 1);
You will still get an error because y(t-1) would be the same as y(0) in the first iteration of the loop. So, you have to start the loop at t = 2:50:
for t = 2:50

Image Analyst
Image Analyst el 31 de En. de 2024

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