plot() and fplot() give different results for the same function

18 visualizaciones (últimos 30 días)
I'm trying to plot the function
between 0 and 100 (not including zero of course), but am running into a problem. When I use
x = linspace(0, 100, 10000);
y = 2.*sqrt(1+x)+((sin(sqrt(x).*pi).*sin(sqrt(1+x).*pi).*(2.*x+1))/(sqrt(x))) - 2.*sqrt(1+x).*cos(sqrt(x).*pi).*cos(sqrt(1+x).*pi);
plot(x,y);
I don't get the result I expected, which is the graph occasionally intersecting y = 0. However, by doing
fplot(@(x) 2.*sqrt(1+x)+((sin(sqrt(x).*pi).*sin(sqrt(1+x).*pi).*(2.*x+1))/(sqrt(x))) - 2.*sqrt(1+x).*cos(sqrt(x).*pi).*cos(sqrt(1+x).*pi), [0 100]);
I do get the result I expected.
I can't just use fplot, as I do need to use the variable y for other things, so I'm not sure what to do or what is even happening here. Any help would be greatly appreciated.

Respuesta aceptada

Bruno Luong
Bruno Luong el 15 de Feb. de 2024
Editada: Bruno Luong el 15 de Feb. de 2024
Your coding is wrong: Replace "/" with "./"

Más respuestas (1)

Torsten
Torsten el 15 de Feb. de 2024
Editada: Torsten el 15 de Feb. de 2024
x = linspace(0, 100, 10000);
y = 2*sqrt(1+x)+sin(sqrt(pi)*x).*sin(sqrt(1+x)*pi).*(2*x+1)./sqrt(x) - 2*sqrt(1+x).*cos(sqrt(x)*pi).*cos(sqrt(1+x)*pi);
plot(x,y);
hold on
f = @(x)2*sqrt(1+x)+sin(sqrt(pi)*x).*sin(sqrt(1+x)*pi).*(2*x+1)./sqrt(x) - 2*sqrt(1+x).*cos(sqrt(x)*pi).*cos(sqrt(1+x)*pi);
fplot(f,[0 100])
  1 comentario
Bruno Luong
Bruno Luong el 15 de Feb. de 2024
Editada: Bruno Luong el 15 de Feb. de 2024
I believe fplot ezplot replace "*" "/" "^" etc... with elementwise operators ".*" "./', ".^". It interprets as standard math notation.
This how charming or quirking MATLAB is, depending on your taste.

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