Using continous time in Matlab editor

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Olutayo Omotoso
Olutayo Omotoso el 25 de Feb. de 2024
Respondida: Olutayo Omotoso el 28 de Feb. de 2024
In the code below, I need to use continous time to generate phi. I want to achieve this in MATLAB editor. I can do this in Simulink using simulink clock block. I want the time t in the editor's script to emulate the clock's block time. Kindly help.
V1 = 18; % Input voltage
R = 7.2; % Load resistance
a = 0 * (2*pi/360); % pulse shift angle (rad)
fs = 70000; % Switching frequency
phi = pi* ((31*2/360) - (0.028*sin(2*pi*t)))); % Phase shift (pi.d in rad) & t is time

Respuesta aceptada

Walter Roberson
Walter Roberson el 25 de Feb. de 2024
Pi = sym(pi);
syms t
phi = Pi * ((31*2/360) - (0.028*sin(2*Pi*t))) % Phase shift (pi.d in rad) & t is time
phi = 
phi is expressed in continuous time t
I have to wonder whether your actual equation is
phi = Pi * ((31*2/360)) - (0.028*sin(2*Pi*t))
phi = 
fplot(phi, [0 10])

Más respuestas (2)

Alexander
Alexander el 25 de Feb. de 2024
Maybe something simple like that:
V1 = 18; % Input voltage
R = 7.2; % Load resistance
t = 0:0.001:3*pi;
a = 0 * (2*pi/360); % pulse shift angle (rad)
fs = 70000; % Switching frequency
phi = pi* ((31*2/360) - (0.028*sin(2*pi*t))); % Phase shift (pi.d in rad) & t is time
plot(t,phi)
  3 comentarios
Alexander
Alexander el 25 de Feb. de 2024
Editada: Alexander el 25 de Feb. de 2024
Yes of cause. It depends of what you are expecting.
Alexander
Alexander el 25 de Feb. de 2024
If forgotten a remark. If fs is the sample frequency just replace 0.001 by 1/70000.

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Olutayo Omotoso
Olutayo Omotoso el 28 de Feb. de 2024
Thanks you all for your help

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