how to do for loop 2nd level?

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Arif
Arif el 11 de Mzo. de 2024
Comentada: Arif el 16 de Mzo. de 2024
hi guys, i want to do :
XY :
AA
AB
AC
AD
..
QQ
but this error happened.
  1 comentario
Arif
Arif el 11 de Mzo. de 2024
Here is my code
clc
clear
beam = {'A';'B';'C';'D';'E';'F';'G';'H';'I';'J';'K';'L';'M';'N';'O';'P';'Q'}
column = {'A';'B';'C';'D';'E';'F';'G';'H';'I';'J';'K';'L';'M';'N';'O';'P';'Q'}
for i = 1 : length(beam)
x(i) = string(beam(i))
for j = 1 : length(column)
y(j) = string(column(j))
xy(i) = append(x(i),y(j))
end

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Rik
Rik el 11 de Mzo. de 2024
Editada: Rik el 11 de Mzo. de 2024
Your code can be optimized, but here are the minimal changes.
beam = {'A';'B';'C';'D';'E';'F';'G';'H';'I';'J';'K';'L';'M';'N';'O';'P';'Q'};
column = {'A';'B';'C';'D';'E';'F';'G';'H';'I';'J';'K';'L';'M';'N';'O';'P';'Q'};
xy=repmat("",numel(beam)*numel(column),1);
k=0;
for i = 1 : numel(beam)
x = string(beam(i));
for j = 1 : numel(column)
y = string(column(j));
k=k+1;
xy(k) = x+y;
end
end
xy
xy = 289×1 string array
"AA" "AB" "AC" "AD" "AE" "AF" "AG" "AH" "AI" "AJ" "AK" "AL" "AM" "AN" "AO" "AP" "AQ" "BA" "BB" "BC" "BD" "BE" "BF" "BG" "BH" "BI" "BJ" "BK" "BL" "BM"
Now for the more compact version (using implicit expansion and transposing with .'):
beam = {'A';'B';'C';'D';'E';'F';'G';'H';'I';'J';'K';'L';'M';'N';'O';'P';'Q'};
column = {'A';'B';'C';'D';'E';'F';'G';'H';'I';'J';'K';'L';'M';'N';'O';'P';'Q'};
xy = string(beam).'+string(column);
xy = xy(:);
xy
xy = 289×1 string array
"AA" "AB" "AC" "AD" "AE" "AF" "AG" "AH" "AI" "AJ" "AK" "AL" "AM" "AN" "AO" "AP" "AQ" "BA" "BB" "BC" "BD" "BE" "BF" "BG" "BH" "BI" "BJ" "BK" "BL" "BM"
Or perhaps even this:
beam = string(num2cell('A':'Q'));
column = string(num2cell('A':'Q'));
xy = reshape(beam+column.',[],1);
xy
xy = 289×1 string array
"AA" "AB" "AC" "AD" "AE" "AF" "AG" "AH" "AI" "AJ" "AK" "AL" "AM" "AN" "AO" "AP" "AQ" "BA" "BB" "BC" "BD" "BE" "BF" "BG" "BH" "BI" "BJ" "BK" "BL" "BM"

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