错误使用 QPSKDemodulator The input must be a column vector. 出错 q (line 45) dataOut = qpskDemod(rxSig);

clc;

% 参数设置

N = 20; % 发射天线数

Nr = 3; % 接收天线数

NumRF = 2; % RF镜个数

numRF=2^NumRF;%RF镜个数对应的信道数量

SNR_dB = 15; % 信噪比 (dB)

SNR = 10^(SNR_dB/10); % 信噪比转换为线性尺度

% QPSK调制参数

M = 4; % 调制阶数 (QPSK)

k = log2(M); % 每个符号的比特数

Es = 1; % 符号能量

Eb = Es/k; % 每比特能量

% 生成随机比特序列，确保总比特数可以被 (N*k) 整除

numBits = 1e5;

numBits = numBits - mod(numBits, N*k); % 确保整除

dataIn = randi([0 1], numBits, 1);

% QPSK调制

qpskMod = comm.QPSKModulator('BitInput', true);

txSig = qpskMod(dataIn); % 直接使用生成的比特序列

% RIS配置

H1 = (randn(N, numRF) + 1i*randn(N, numRF))/sqrt(2); % 发射天线到RF镜的信道

H2 = (randn(Nr,numRF) + 1i*randn(Nr,numRF))/sqrt(2); % RF镜到接收天线的信道

Phi = diag(exp(1i*2*pi*rand(numRF,1))); % RF镜相位调整

% 信道传输

% 调整txSig的形状以适配H1

txSig_reshaped = reshape(txSig, N, []); % 调整txSig的形状为 N x (length(txSig)/N)

% 确认计算的维度

composite_channel = H1' * txSig_reshaped; % 正确计算应为 numRF x M

% 通过Phi (numRF x numRF) 和 H2 (numRF x Nr)处理信号

% Phi * composite_channel 的结果为 numRF x M

% H2 * (Phi * composite_channel) 的结果为 Nr x M

rxSig = sqrt(SNR/N) * H2 * Phi * composite_channel + (randn(Nr, size(composite_channel, 2)) + 1i*randn(Nr, size(composite_channel, 2)))/sqrt(2);

% 接收端处理

qpskDemod = comm.QPSKDemodulator('BitOutput', true);

dataOut = qpskDemod(rxSig);

% 计算BER

[numErrors, ber] = biterr(dataIn, dataOut);

fprintf('BER = %f\n', ber);

Answer 1

[Andreas Goser]

From the basic programming, this can be explained like this:

rxSig is a 3x2500 matrix when you call qpskDemod. It means it is not a column vector.

The question now is whether this already helps you, or if there is a need to understand the application as a whole?