solving non-linear ODE

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문기 el 8 de Mayo de 2024
Comentada: 문기 el 9 de Mayo de 2024
I'm trying to solve ODE using MATLAB(ode45), but not working.
In this case, how can I modify code
Here is existing code
a = theta_m / erf(Z)/(2*sqrt(alpha * t));
c = (1 - theta_m)/(erfc(Z)/(2*sqrt(alpha * t)));
term1 = simplify(a - c);
term2 = (sqrt(pi)*rho*del_H/(2*k*(T1-T0))) * exp((Z)^2/(4*alpha^2*t^2));
dZdt = @(t,Z) term1/term2
tspan = [0 5];
Z0 = 0;
[t,Z] = ode45(dZdt, tspan, Z0);
Error using superiorfloat
Inputs must be floats, namely single or double.
Error in odearguments (line 114)
dataType = superiorfloat(t0,y0,f0);
Error in ode45 (line 107)
odearguments(odeIsFuncHandle,odeTreatAsMFile, solver_name, ode, tspan, y0, options, varargin);
Error in untitled3 (line 27)
[t,Z] = ode45(dZdt, tspan, Z0);
Thanks for your support

Respuesta aceptada

Sam Chak
Sam Chak el 8 de Mayo de 2024
I didn't modify your equations (except for removing the 'simplify' part), but you need to provide values for the parameters in the 'ode' function. Some division terms encounter a division-by-zero singularity (referred to as Infinity in layman's terms) when and . Therefore, I adjusted the code by using small positive values for tspan(1) and Z0.
%% Define the differential equation in a function object
function dZdt = ode(t, Z)
% parameters
theta_m = 1;
alpha = 1;
rho = 1;
del_H = 1;
k = 1;
T1 = 1;
T0 = 0;
% terms
a = theta_m / erf(Z) / (2*sqrt(alpha*t));
c = (1 - theta_m)/(erfc(Z)/(2*sqrt(alpha * t)));
term1 = a - c;
term2 = (sqrt(pi)*rho*del_H/(2*k*(T1-T0))) * exp((Z)^2/(4*alpha^2*t^2));
% ODE
dZdt = term1/term2;
end
tspan = [0.0001 5];
Z0 = 0.0001;
[t, Z] = ode45(@ode, tspan, Z0);
plot(t, Z), grid on, xlabel('t'), ylabel('Z(t)'), title('Time response of Z')
  1 comentario
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문기 el 9 de Mayo de 2024
the key was the fact that it cannot be divided with 0.
Thank you

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Más respuestas (1)

Steven Lord
Steven Lord el 8 de Mayo de 2024
This line suggests you're performing operations with symbolic variables.
term1 = simplify(a - c);
If so, you're probably going to need to use matlabFunction or odeFunction to create the anonymous function rather than simply dividing your terms (which won't substitute values into the symbolic expression) or use dsolve.
See the section on solving ODEs in the Symbolic Math Toolbox documentation for more information about using dsolve.

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