Creating a matrix for specific variables

t=0:0.0000001:0.0001;

DABi=zeros(1,length(t));

y=zeros(1,length(t));

vin=zeros(1,length(t));

vo=zeros(1,length(t));

L=27e-6;

f=50e3;

vo=square(2*pi*f*t);

for i=1:length(y)

j=mod(i-30,length(y))+1;

vin(i)=vo(j);

end

vin=800.*vin;

vo=400.*vo;

for i=2:length(t)

DABi(i)= ((vin(i)-vo(i))/L)*(t(i)-t(i-1))+DABi(i-1);

end

DABi=DABi-mean(DABi);

plot(t,DABi,"m");

hold on;

plot(t,vinp,"b");

hold on;

plot(t,vout,"r");

grid on;

legend('Current','Input Voltage', 'OUtput Voltage')

xlim([0 0.0001])

hold off;

I want to create 2 different matrices first based on the Input voltage and current and the second based on Output voltage and current. Let discuss only input voltage and current case.

For the first matrix I want to focus only on the point when input voltage switches (just the switching instance) to 400 and -400 value (All the rest point should be excluded from the matrix). When voltage switches to 400 value I want to look at current if it is negative I should get 1 if it is zero I should get 0 if it is positive value I should get +1. Whereas for -400 value if current is positive I should get 1 if it is zero I should get 0 if it is negative value I should get -1

Answer 1

[surya venu]

Hi,

To create the matrix based on the Input voltage and current focusing only on the points where the input voltage switches to 400 or -400, and associating the current values accordingly, we can follow these steps:

1. Identify the switching points: We need to find the indices where vin switches to 400 or -400. This can be done by looking for the differences between consecutive elements and finding where these changes occur.
2. Classify the current at these points: Based on the value of the current (DABi) at these switching points, classify according to the rules you provided.

Here is the MATLAB code

t = 0:0.0000001:0.0001;
DABi = zeros(1,length(t));
vin = zeros(1,length(t));
vo = zeros(1,length(t));
L = 27e-6;
f = 50e3;
vo = square(2*pi*f*t);
for i = 1:length(vo)
    j = mod(i-30,length(vo)) + 1;
    vin(i) = vo(j);
end
vin = 800.*vin;
vo = 400.*vo;
for i = 2:length(t)
    DABi(i) = ((vin(i) - vo(i)) / L) * (t(i) - t(i-1)) + DABi(i-1);
end
DABi = DABi - mean(DABi);

% Finding the switching points
switchingIndices = find(diff(vin) ~= 0) + 1;

inputSwitchMatrix = zeros(length(switchingIndices), 2);

for i = 1:length(switchingIndices)
    idx = switchingIndices(i);
    inputVoltage = vin(idx);
    currentAtSwitch = DABi(idx);
    
    % Determine the matrix value based on your conditions
    if inputVoltage == 400
        % For 400V switch
        if currentAtSwitch > 0
            inputSwitchMatrix(i, :) = [400, 1];
        elseif currentAtSwitch == 0
            inputSwitchMatrix(i, :) = [400, 0];
        else\
            inputSwitchMatrix(i, :) = [400, -1];
        end
    elseif inputVoltage == -800
        % For -400V switch, note your vin is actually 800 or -800
        if currentAtSwitch > 0
            inputSwitchMatrix(i, :) = [-800, 1];
        elseif currentAtSwitch == 0
            inputSwitchMatrix(i, :) = [-800, 0];
        else
            inputSwitchMatrix(i, :) = [-800, -1];
        end
    end
end

Hope it helps.

[ammar ansari]

Need few changes but works like a charm. Thanks