I am finding issues in PDEPe which shows time integration failure again and again

4 visualizaciones (últimos 30 días)
"Warning: Failure at t=2.088125e-04. Unable to meet integration tolerances without reducing the step size
below the smallest value allowed (4.336809e-19) at time t. "
This message is being shown for running my code. I am uploading my code below.
clear all
clc
close all
m=0;
x=linspace(0,1,1001);
t=linspace(0,1,1001);
options = odeset('RelTol', 1e-3, 'AbsTol', 1e-6,'MaxStep', 0.1);
sol=pdepe(m,@coupledpde_BACD,@coupledic_BACD,@coupledbc_BACD,x,t,options);
b=sol(:,:,1);
figure(1)
surf(x,t,b)
xlabel('x')
ylabel('t')
zlabel('b(x,t)')
grid on
title('Bacterial distribution');
view([150 25])
colorbar
colormap jet
for j=[1 11 101]
ylim([0,1.2])
figure(2)
hold on
plot(x,b(j,:),LineWidth=2)
title("Particle Concentration Profile at t= (1, 11, 101)*td")
xlabel("Characteristic length")
ylabel('bacteria Concentration')
end
function [c,f,s]= coupledpde_BACD(x,t,u, dudx)
Db=10^-12;
Dc=10^-9;
X0=10^-9;
% X0=linspace(10^-11,10^-9,100);
% Db=linspace(10^-13,10^-12,100);
c=1;
s=0;
l=[pi/2 3*pi/2 5*pi/2];
A=4.*(cos(l)-1)./(2.*l-sin(2.*l));
mob_ratio=X0/Dc;
d_ratio=Db/Dc;
f=(d_ratio).*dudx-u*(mob_ratio)./(1+exp(-l(1)^2.*t).*A(1).*sin(l(1).*x)).*(exp(-l(1)^2.*t).*A(1).*cos(l(1).*x).*l(1));
end
function u0 = coupledic_BACD(x)
u0=1;
end
function [pl,ql,pr,qr]= coupledbc_BACD(xl,ul,xr,ur,t)
pl=ul;
ql=0;
pr=0;
qr=1;
end
please help me find the issue in the code
  4 comentarios
Torsten
Torsten el 22 de Jun. de 2024
Editada: Torsten el 22 de Jun. de 2024
At the moment, you set
(d_ratio).*dudx(@x=1)-u(@x=1)*(mob_ratio)./(1+exp(-l(1)^2.*t).*A(1).*sin(l(1))).*(exp(-l(1)^2.*t).*A(1).*cos(l(1)).*l(1)) = 0
Is this what you mean by "zero neumann boundary condition" ?

Iniciar sesión para comentar.

Respuestas (1)

Umang Pandey
Umang Pandey el 16 de Jul. de 2024
Hi Aaditya,
This error message indicates that the problem you are trying to solve is too stiff for the ODE solver you are trying to use, or that it includes a singularity.
It has been explained by the MathWorks Support Staff in the following MATLAB answer:
Hope this helps!
Best,
Umang

Categorías

Más información sobre Programming en Help Center y File Exchange.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by