Remove column based on row value

1 visualización (últimos 30 días)
Jonathan Lam
Jonathan Lam el 3 de Jul. de 2024
Comentada: Taylor el 3 de Jul. de 2024
Hello all,
A bit new to MATLAB but I have a matrix M that is [2x19]. In the first row are x-values derived from another function, but I want to return a new matrix that excludes the columns in M with an x-value larger than 4 in this case
100 0.909090909090909 1 1.01010101010101 1.13636363636364 1.29870129870130 1.50000000000000 1.51515151515152 1.81818181818182 2 2.27272727272727 2.50000000000000 3 3.03030303030303 3.50000000000000 4 4.50000000000000 4.54545454545455 5
18 1 0.909090909090909 0.900000000000000 0.800000000000000 0.700000000000000 0.606060606060606 0.600000000000000 0.500000000000000 0.454545454545455 0.400000000000000 0.363636363636364 0.303030303030303 0.300000000000000 0.259740259740260 0.227272727272727 0.202020202020202 0.200000000000000 0.181818181818182
I know it might seem like a simple question but I can't seem to use the M = M(M(1,:)<=4, M(:,1) nonmenclature correctly. Would appreciate any help

Respuesta aceptada

Taylor
Taylor el 3 de Jul. de 2024
A = [1 2 5; 3 4 6; 2 8 9]
A = 3x3
1 2 5 3 4 6 2 8 9
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
colsToKeep = ~any(A > 4, 1)
colsToKeep = 1x3 logical array
1 0 0
B = A(:, colsToKeep)
B = 3x1
1 3 2
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
  2 comentarios
Jonathan Lam
Jonathan Lam el 3 de Jul. de 2024
Thanks so much, I was able to get it with your help.
Taylor
Taylor el 3 de Jul. de 2024
Great! You were on the right track with the logical indexing. any and all are quite useful functions when performing logical indexing.

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre Matrix Indexing en Help Center y File Exchange.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by