Adding a column to a UITable and then using it.

3 visualizaciones (últimos 30 días)
Alessandro Livi
Alessandro Livi el 21 de Jul. de 2024
Comentada: Voss el 22 de Jul. de 2024
After a few hours of trying I finally was able to add a column to a UITable
A = zeros([1 size(app.StimInputTable.Data,1)]);
app.StimInputTable.Data.Var4 = A'; % Have to make A a column vector!
for ii = 1:size(app.StimInputTable.Data,1)
app.StimInputTable.Var4(ii) = ...
app.StimInputTable.Data.Var3(ii)/app.StimInputTable.Data.Var2(ii);
But now...
assigning a value to Our new column Var4 gives me
Unrecognized method, property, or field 'Var4' for class 'matlab.ui.control.Table'.
It know what app.StimInputTable.Data.Var3(ii)/app.StimInputTable.Data.Var2(ii);
is so now put it in Var4! How hard can that be?
K>> app.StimInputTable.Data
ans =
4×4 table
Var1 Var2 Var3 Var4
____ ____ ____ ____
4 5 0 0
5 4 1 0
2 3 2 0
3 2 5 0
I can do it 1 row at a time from theCommand window:
K>> app.StimInputTable.Data
ii = 1 (etc)
K>> app.StimInputTable.Data.Var4(ii) = app.StimInputTable.Data.Var3(ii)/app.StimInputTable.Data.Var2(ii)
Although the "answer" I get is my whole
app =
MouseOdor4 with properties:
MouseOdor: [1×1 Figure]
all the properties of the whole app I won't bore you with
K>> app.StimInputTable.Data
ans =
4×4 table
Var1 Var2 Var3 Var4
____ ____ ____ _______
4 5 0 1
5 4 1 2
2 3 2 0.66667
3 2 5 2.5
Look it worked!
Next step if you don't mind anwering is to sort the table by the Var4 column
  1 comentario
Alessandro Livi
Alessandro Livi el 21 de Jul. de 2024
BTW I tried addvars() for a while as help said to do but never got that to work following all the examples the best I could

Iniciar sesión para comentar.

Respuesta aceptada

Voss
Voss el 21 de Jul. de 2024
Editada: Voss el 21 de Jul. de 2024
app.StimInputTable.Data.Var4 = app.StimInputTable.Data.Var3./app.StimInputTable.Data.Var2;
%                 ^^^^^ you were missing the .Data
  4 comentarios
Alessandro Livi
Alessandro Livi el 22 de Jul. de 2024
Added some string stuff which completes but now when I exit the callback it halts here so maybe that is a clue?
methods (Access = protected, Sealed = true)
function newCallback = createCallbackFcn(app, callback, requiresEventData)
if nargin == 2
requiresEventData = false;
end
ams = appdesigner.internal.service.AppManagementService.instance();
newCallback = @(source, event)executeCallback(ams, ...
app, callback, requiresEventData, event);
end
Is there some magic I have to do at the end of a callback function?
Voss
Voss el 22 de Jul. de 2024
No magic required. What is the problem you are describing?

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre Develop Apps Using App Designer en Help Center y File Exchange.

Productos


Versión

R2023b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by