BTW I tried addvars() for a while as help said to do but never got that to work following all the examples the best I could
Adding a column to a UITable and then using it.
3 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Alessandro Livi
el 21 de Jul. de 2024
Comentada: Voss
el 22 de Jul. de 2024
After a few hours of trying I finally was able to add a column to a UITable
A = zeros([1 size(app.StimInputTable.Data,1)]);
app.StimInputTable.Data.Var4 = A'; % Have to make A a column vector!
for ii = 1:size(app.StimInputTable.Data,1)
app.StimInputTable.Var4(ii) = ...
app.StimInputTable.Data.Var3(ii)/app.StimInputTable.Data.Var2(ii);
But now...
assigning a value to Our new column Var4 gives me
Unrecognized method, property, or field 'Var4' for class 'matlab.ui.control.Table'.
It know what app.StimInputTable.Data.Var3(ii)/app.StimInputTable.Data.Var2(ii);
is so now put it in Var4! How hard can that be?
K>> app.StimInputTable.Data
ans =
4×4 table
Var1 Var2 Var3 Var4
____ ____ ____ ____
4 5 0 0
5 4 1 0
2 3 2 0
3 2 5 0
I can do it 1 row at a time from theCommand window:
K>> app.StimInputTable.Data
ii = 1 (etc)
K>> app.StimInputTable.Data.Var4(ii) = app.StimInputTable.Data.Var3(ii)/app.StimInputTable.Data.Var2(ii)
Although the "answer" I get is my whole
app =
MouseOdor4 with properties:
MouseOdor: [1×1 Figure]
all the properties of the whole app I won't bore you with
K>> app.StimInputTable.Data
ans =
4×4 table
Var1 Var2 Var3 Var4
____ ____ ____ _______
4 5 0 1
5 4 1 2
2 3 2 0.66667
3 2 5 2.5
Look it worked!
Next step if you don't mind anwering is to sort the table by the Var4 column
Respuesta aceptada
Más respuestas (0)
Ver también
Categorías
Más información sobre Develop Apps Using App Designer en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!